For each of the following, find the transition matrix from B, to B, and the transition matrix from B2 to Bi. Be sure to label wh
ich is which. Then use the transition matrices to write the given vector relative to the other basis. You may use a calculator for row reduction (just show the original matrix and it's reduced row echelon form). You may also use a calculator for finding matrix inverses. (a) V =R2, B = {(-4, 3), (6,2)), B2 = {(2, -3),(-1,4)}, TB = (2,-5). = {(0,4,-1),(1,2,-6), (2, -2,0)}, (b) V =R3, B1 = {(3,2,1),(0,3, -2), (0, -2, 1)}, B 7 B2 = (4, -5,3). (e) V = P2, B, = {rº, 1, 1), B2 = {4.x2 – 2x + 5, 2x2 – 3.2 +1, 4.r? – 2}, (6)b = (-4,3,1).
1 answer:
You might be interested in
The picture in the attached figure
Part 1) <span>What is the total area of the swimming pool?
</span>
we know that
<span>area of the swimming pool=area rectangle-area semi circle
area rectangle=20*36-----> 720 ft</span>²
area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²
area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²
the answer Part 1) is
The area of the swimming pool is 592.83 ft²
Part 2) <span>What is the perimeter of the swimming pool?
</span>
perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft
perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft
the answer Part 2) is
122.26 ft
Part 1) <span>What is the total area of the swimming pool?
</span>
we know that
<span>area of the swimming pool=area rectangle-area semi circle
area rectangle=20*36-----> 720 ft</span>²
area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²
area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²
the answer Part 1) is
The area of the swimming pool is 592.83 ft²
Part 2) <span>What is the perimeter of the swimming pool?
</span>
perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft
perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft
the answer Part 2) is
122.26 ft