Answer:
V = 9.682 × 10^(-6) V
Explanation:
Given data
thick = 190 µm
wide = 4.20 mm
magnitude B = 0.78 T
current i = 32 A
to find out
Calculate V
solution
we know v formula that is
V = magnitude× current / (no of charge carriers ×thickness × e
here we know that number of charge carriers/unit volume for copper = 8.47 x 10^28 electrons/m³
so put all value we get
V = magnitude× current / (no of charge carriers ×thickness × e
V = 0.78 × 32 / (8.47 x 10^28 × 190 × 1.602 x 10^(-19)
V = 9.682 × 10^(-6) V
Answer:
(a). The draw-down at a distance 200 m from the well after pumping for 50 hr is 5.383 m.
(b). The draw-down at a distance 200 m from the well after pumping for 50 hr is 6.707 m.
Explanation:
Given that,
Energy 
Transmissivity 
Storage coefficient 
Distance r= 200 m
We need to calculate the draw-down at a distance 200 m from the well after pumping for 50 hr
Using formula of draw-down

Put the value into the formula


We need to calculate the draw-down at a distance 200 m from the well after pumping for 200 hr
Using formula of draw-down

Put the value into the formula


Hence, (a). The draw-down at a distance 200 m from the well after pumping for 50 hr is 5.383 m.
(b). The draw-down at a distance 200 m from the well after pumping for 200 hr is 6.707 m.
Answer:
B. The object reached terminal velocity.
Explanation:
At t=0.5, the acceleration is 0, so the velocity is constant. So the object has reached terminal velocity, and the net force is 0.