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Elden [556K]
4 years ago
5

A machine can never be 100% efficient because some work is always lost due to .

Physics
2 answers:
konstantin123 [22]4 years ago
6 0

Efficiency of machine is defined by

\eta = \frac{W_{output}}{Q_{input}}

here we know that

W_{output} = output useful work

Q_{input} = input energy

Now here if we obtain output work same as input thermal energy then it is 100% efficient

but this is only possible when we have no energy loss while it is not possible due to many reasons

one of the main cause of energy loss is friction

So when machine working there must be friction between its working parts due to which out input energy is lost in different parts and hence we can never be 100% efficient machine.

So here main reason is FRICTIONAL LOSS

klasskru [66]4 years ago
5 0
Friction
Hope it helped
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Which description does the phrase "mechanical advantage" most closely relate to?
yKpoI14uk [10]
<span>the ratio of the force produced by a machine to the force applied to it, used in assessing the performance of a machine. I would say the answer is D, but i'm not sure. :)</span>
4 0
3 years ago
What will happen for Potential energy of a body if the mass is dobled keeping height constant​
4vir4ik [10]
<h3><u>Given </u><u>:</u><u>-</u></h3>

  • The mass of the body is doubled
  • The height of the body is constant

<h3><u>Solution </u><u>:</u><u>-</u><u> </u></h3>

We know that ,

Potential energy = mgh

<u>Therefore</u><u>, </u>

We can say that,

PE is directly proportional to Mass of the body

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

PE of the body = 2m * g * h. ...eq( I)

From (I) , we can conclude that, If mass of the body get doubled then its PE will also be doubled .

4 0
3 years ago
If a 4500 kg car is traveling with an acceleration of 35.2 m/s/s, what is the force acting on it?
Elena L [17]

Answer:

<h2>158,400 J</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 4500 × 35.2 = 158400

We have the final answer as

<h3>158,400 J</h3>

Hope this helps you

3 0
2 years ago
Hi
romanna [79]

Answer:HERE IS YOUR ANSWER

THE POINTS ARE

IF WE PUT THE OBJECT BETWEEN THE FOCUS

AND THE POLE

THEN THE IMAGE FORMED WILL be MAGNIFIED

If that’s not what you are looking for, try this one:

For concave mirror the virtual image is formed when the object is kept in between the pole and the focus.  

Given here the "size of the image" is twice to that of the object.

Hence, it is consider that the magnification is +2.

So, the magnification value is positive and the image formed will be "virtual and erect". Thus, the object should be kept in between the "pole and the focus" in concave mirror."

Explanation:

3 0
4 years ago
Read 2 more answers
An unknown mass is on a flat frictionless surface and a 2 kg object is attached to it with a string going over pulleyt mounted t
Lynna [10]

Answer:

Explanation:

F=ma

F in this case is the gravity acting on the 2kg object. Acceleration of gravity is 9.8 m/s^2. SF=ma, so

F = 2kg*(9.8 m/s^2) = 19.6 N

Now use this force to determine the mass of the object on the table:

F=ma

19.6 N (1N=kg*m/s^2) = m*(1.8 m/s^2)

m = 10.89 kg

3 0
3 years ago
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