Dalton thought that atoms were indivisible particles, and Thomson's discovery of the electron proved the existence of subatomic particles. ... The positive and negative charges cancel producing a neutral atom. images.tutorvista.com. Later discoveries by Rutherford and others lead to additional revisions to atomic theory.
If the ball does not have a propeller or jet engine on it, then it is an object
in free fall. That means its downward speed grows by 9.8 m/s for every
second that it's in the air.
If it happens to be traveling upward at the moment, then that won't last long.
Its upward speed is decreasing by 9.8 m/s every second. It will eventually
run out of upward gas and start moving downward. At that instant, you might
say that the direction of its velocity has changed by 180 degrees.
The answer should be B - lasts longer.
Based on the calculations, the angle through which the tire rotates is equal to 4.26 radians and 244.0 degrees.
<h3>How to calculate the angle?</h3>
In Physics, the distance covered by an object in circular motion can be calculated by using this formula:
S = rθ
<u>Where:</u>
- r is the radius of a circular path.
- θ is the angle measured in radians.
Substituting the given parameters into the formula, we have;
1.87 = 0.44 × θ
θ = 1.87/0.44
θ = 4.26 radians.
Next, we would convert this value in radians to degrees:
θ = 4.26 × 180/π
θ = 4.26 × 180/3.142
θ = 244.0 degrees.
Read more on radians here: brainly.com/question/19758686
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Answer:
0.0241875 m
Explanation:
= Mass of quarterback = 80 kg
= Mass of football = 0.43 kg
= Velocity of quarterback
= Velocity of football = 15 m/s
Time taken = 0.3 seconds
In this system as the linear momentum is conserved
![m_1v_1+m_2v_2=0\\\Rightarrow v_1=-\frac{m_2v_2}{m_1}\\\Rightarrow v_1=-\frac{0.43\times 15}{80}\\\Rightarrow v_1=0.080625\ m/s](https://tex.z-dn.net/?f=m_1v_1%2Bm_2v_2%3D0%5C%5C%5CRightarrow%20v_1%3D-%5Cfrac%7Bm_2v_2%7D%7Bm_1%7D%5C%5C%5CRightarrow%20v_1%3D-%5Cfrac%7B0.43%5Ctimes%2015%7D%7B80%7D%5C%5C%5CRightarrow%20v_1%3D0.080625%5C%20m%2Fs)
Assuming this velocity is constant
![Distance=Velocity\times Time\\\Rightarrow Distance=0.080625\times 0.3\\\Rightarrow Distance=0.0241875\ m](https://tex.z-dn.net/?f=Distance%3DVelocity%5Ctimes%20Time%5C%5C%5CRightarrow%20Distance%3D0.080625%5Ctimes%200.3%5C%5C%5CRightarrow%20Distance%3D0.0241875%5C%20m)
The distance the quarterback will move in the horizontal direction is 0.0241875 m