Newton's third law of motion
Explanation:
Newton's third law of motion states that:
<em>"When an object A exerts a force on an object B (action force), then object B exerts an equal and opposite force (reaction force) on object A"</em>
It is important to note that this law is always valid, even when it seems it is not.
Consider for example the gravitational force that the Earth exerts on your body (= your weight). We can say that this is the action force. It may seems that there is no reaction force in this case. However, this is not true: in fact, your body also exerts an equal and opposite force on the Earth, and this is the reaction force. The reason that explains why we don't notice any effect on Earth due to this force is that the mass of the Earth is much larger than your mass, therefore the acceleration produced on the Earth because of the force you apply is negligible.
It is also important to note that the action-reaction pair of forces always act on two different objects, so they never appear in the same free-body diagram.
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Just subsitute and easy
v=55m/s
m=100kg
KE=(0.5)(100kg)(55m/s)^2
KE=(50kg)(3025 m^2/s^2)
KE=151250 J
2nd option
Answer:
8 seconds
Explanation:
Since the carspeed is in km/h, we need equal units, so we will make 100.0m 0.1000km.
Then we need to find how long it takes the car to travel 0.1km
We can use the formula distance=speed * time and get
0.1=45 * time
Therefore we get .002222... hours
Multiplying this by 3600 (to get seconds, 60x60), we get 8 seconds
Answer:
angular resolution = 0.07270° = 1.269 × 
rad
greatest distance from the camera = 118.20 m = 0.118 km
Explanation:
given data
diameter = 0.50 mm = 0.5 × m
distance apart = 15 cm = 15× 
m
wavelength λ = 520 nm = 520 × 
m
to find out
angular resolution and greatest distance from the camera
solution
first we expression here angular resolution that is
sin θ = 
.......................1
put here value λ is wavelength and d is diameter
we get
sin θ = 
θ = 0.07270° = 1.269 × rad
and
distance from camera is calculate here as
θ = 
.................2
I = 
I = 118.20 m = 0.118 km
