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Anna11 [10]
3 years ago
9

What could you do to decrease the rate at which salt dissolves in water?

Physics
1 answer:
kotykmax [81]3 years ago
3 0

Answer:

use hot water

Explanation:

hot water helps dissolve things faster

You might be interested in
If you decrease the length of a wire, what effect will it have on resistance
attashe74 [19]
As the length increases, resistance increases, as a result current decreases.
7 0
4 years ago
In a crash test, a car with a mass of 1600 kg is initially moving at a speed of 20 m/s just before it collides with a barrier. T
Andrews [41]

Answer:

The answer to the given points can be defined as follows:

Explanation:

In point 1:

\bold{v_f^2=  v_i^2+2as}\\\\\to v_f=0\\\\\to v_i=20 \frac{m}{s}\\\\\to s= 4.50\ m -3.60 \ m \\\\

      =0.9 \ m \\

put the value in the above formula:

\to 0=  20^2+2 \times a \times 0.9\\\\\to -1.8\ a=400\\\\\to -a= \frac{400}{1.8} \\\\ \to a= -222.22\ \  \frac{m}{s^2}

 \bold{v_f=v_i+at}\\\\\to 0=20+ (-222.22)t\\\\\to  222.22t=20\\\\\to t=\frac{20}{222.22}\\\\\to t= 0.0900 \ s\\\\\to v_{avg}=\frac{s}{t}=\frac{0.9}{t}= 10\ \frac{m}{s}

for point 2:

t= 0.0900 \ s  -\text{found above}

for point 3:

\to |a| = 222.22 \frac{m}{s^2} \text{found above}\\\\\to \bold{|F| = m \cdot |a|}\\\\

         =1600 \ kg \times 222.22 \ \frac{m}{s^2} \\\\= 3.55\times 10^{5} \ N

5 0
3 years ago
What is the rotational inertia of an object that rolls without slipping down a 2.00-m-high incline starting from rest, and has a
krek1111 [17]

We will apply the concepts of energy conservation to solve the problem. We know that gravitational potential energy is equivalent to the sum of translational kinetic energy and rotational kinetic energy. Additionally, the relation of the angular velocity with the tangential velocity will be determined to eliminate the angular term and obtain the expression of the Inertia in terms of the data given, therefore, we know that

PE_{g} = KE_{trans} +KE_{rot}

mgh = \frac{1}{2} mv^2+\frac{1}{2}I\omega^2

The angular velocity in terms of tangential velocity and radius is defined as,

\omega = \frac{v}{R}

Replacing,

mgh = \frac{1}{2} mv^2+\frac{1}{2} I(\frac{v}{R})^2

Multiplying by R^2,

gh(mR^2) = \frac{v^2}{2} (mR^2)+\frac{v^2}{2}I

\frac{v^2}{2}I = (gh-\frac{v^2}{2})mR^2

I = (\frac{2gh}{v^2}-1)mR^2

Replacing with our values we have,

I = (\frac{2(9.8)(2)}{6^2}-1)mR^2

I = 0.089mR^2

6 0
3 years ago
A nurse applies a horizontal force of 147 N on a bed that has a mass of 152 kg,The magnitude of the normal force acting on the b
oee [108]

Answer:

1490 N

Explanation:

The force applied by the nurse is horizontal, so there's no vertical component.

Therefore, the normal force is simply equal to the weight of the bed.

N = mg

N = (152 kg) (9.8 m/s²)

N = 1490 N

3 0
3 years ago
Radio waves travel at a speed of 300,000,000 m/s.
garik1379 [7]

Answer:

<h2>3.06 m</h2>

Explanation:

The wavelength of KQFC’s radio wave can be found by using the formula

\lambda =  \frac{v}{f}  \\

v is the velocity

f is the frequency

Fromthe question we have

\lambda =  \frac{300000000}{97900000}  =  \frac{3000}{979}  \\  = 3.064351...

We have the final answer as

<h3>3.06 m</h3>

Hope this helps you

8 0
3 years ago
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