Explanation:
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A driver is traveling along a straight road at the speed limit of 60 mph. After two minutes, she slows at a constant rate to a s
top at a stop light. Two minutes later, the light turns green and she accelerates at a constant rate back up to the speed limit. Three and a half minutes later, she again slows at a constant rate to a stop. After three minutes, she performs a U-turn, then accelerates at a constant rate back up to 60 mph. Two minutes later, she reaches her destination and slows at a constant rate to a stop. Assume that each period of slowing down and speeding up lasts 30 s and that the driver is initially moving in the +x- direction. Create a graph of the driver's velocity versus time that represents her trip.
1 answer:
Explanation :
From the given information, the graph is plotted.
It is given that, a driver is traveling along a straight road at the speed limit of 60 mph. Initially, he was at point A.
After two minutes, she slows at a constant rate to a stop at a stop light. BC shows this part.
Two minutes later, the light turns green and she accelerates at a constant rate back up to the speed limit. CD shows this part.
Three and a half minutes later, she again slows at a constant rate to a stop. DE shows this part.
Hence, this is the required solution.
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Explanation:
It is given that,
Number of turns, N = 200
Area of cross section, A = 8.5 cm²
Magnetic field is directed out of the paper and is, B = 0.06 T
The magnetic field is out of the paper decreases to 0.02 T in 12 milliseconds. We need to find the direction of current induced. The induced emf is given by :
Since,
I is the induced current
According to Lenz's law, the direction of induced current is such that it always opposes the change in current that causes it.
Here, the field is directed out of the plane of the paper, this gives the induced current in counterclockwise direction.
Answer:
Image is twice as large as the object, and inverted
Explanation:
When an object is placed in front of a mirror, the mirror produces an image.
The magnification of the image is a number telling how much the size of the image is enlarged/diminished with respect to the object.
It is given by
where
M is the magnification
y' is the size of the image
y is the size of the object
In this problem,
M = -2
This means that:
So, we can conclude the following:
- The size of the image is twice the size of the real object
- The image is also inverted, because of the presence of the negative sign in the equation
The question is incomplete. The complete question is :
In a certain underdamped RLC circuit, the voltage across the capacitor decreases in one cycle from 5.0 V to 3.8 V. The period of the oscillations is 1.2 microseconds (1.2*10^-6). What is Q?
Solution :
The underdamped RLC circuit
We know in one time period, v = 2v, at t = T,
so,
Now, Q value
∴
= 11.45