A driver is traveling along a straight road at the speed limit of 60 mph. After two minutes, she slows at a constant rate to a s
top at a stop light. Two minutes later, the light turns green and she accelerates at a constant rate back up to the speed limit. Three and a half minutes later, she again slows at a constant rate to a stop. After three minutes, she performs a U-turn, then accelerates at a constant rate back up to 60 mph. Two minutes later, she reaches her destination and slows at a constant rate to a stop. Assume that each period of slowing down and speeding up lasts 30 s and that the driver is initially moving in the +x- direction. Create a graph of the driver's velocity versus time that represents her trip.
1 answer:
Explanation :
From the given information, the graph is plotted.
It is given that, a driver is traveling along a straight road at the speed limit of 60 mph. Initially, he was at point A.
After two minutes, she slows at a constant rate to a stop at a stop light. BC shows this part.
Two minutes later, the light turns green and she accelerates at a constant rate back up to the speed limit. CD shows this part.
Three and a half minutes later, she again slows at a constant rate to a stop. DE shows this part.
Hence, this is the required solution.
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Answer:
33.6371 m
Explanation:
t = Time taken
u = Initial velocity = 20.3 m/s
v = Final velocity
s = Displacement
a = Acceleration = -7 m/s²
Distance traveled in the 0.207 seconds
Distance = Speed × Time
⇒Distance = 20.3×0.207 = 4.2021 m
Equation of motion
Distance traveled by the car while braking is 29.435 m
Total distance measured from the point where the driver first notices the red light is 29.435+4.2021 = 33.6371 m