A driver is traveling along a straight road at the speed limit of 60 mph. After two minutes, she slows at a constant rate to a s
top at a stop light. Two minutes later, the light turns green and she accelerates at a constant rate back up to the speed limit. Three and a half minutes later, she again slows at a constant rate to a stop. After three minutes, she performs a U-turn, then accelerates at a constant rate back up to 60 mph. Two minutes later, she reaches her destination and slows at a constant rate to a stop. Assume that each period of slowing down and speeding up lasts 30 s and that the driver is initially moving in the +x- direction. Create a graph of the driver's velocity versus time that represents her trip.
1 answer:
Explanation :
From the given information, the graph is plotted.
It is given that, a driver is traveling along a straight road at the speed limit of 60 mph. Initially, he was at point A.
After two minutes, she slows at a constant rate to a stop at a stop light. BC shows this part.
Two minutes later, the light turns green and she accelerates at a constant rate back up to the speed limit. CD shows this part.
Three and a half minutes later, she again slows at a constant rate to a stop. DE shows this part.
Hence, this is the required solution.
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Forward thrust has positive values and reverse thrust has negative values.
Thrust is a sudden push or pull in a certain direction.
a)
Flight speed u = 150 km/h
1 km/h = km/s
therefore, 150 km/h = 41.67 km / s
The thrust force represents the horizontal or x-component of momentum equation:
T = 50 * (150 - 41.67)
T = 5416.67 N
Therefore, the value of forward thrust is 5416.67 N.
b)
Now the exhaust velocity is now vertical due to reverse thrust application, then it has a zero horizontal component,
thus thrust equation is:
T = 50 * (0 - 41.67)
T = -2083.5 N
Therefore, the thrust force T is -2083.5 N in the reverse direction.
c)
Now the exhaust velocity and flight velocity is zero, then it has a zero horizontal component, thus thrust is also zero because
T = 0
Therefore, there is no difference in two velocities in x direction.
The given question is incomplete, the complete question is,
"The idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse thrust if the jet is properly deflected. Suppose that while the aircraft rolls down the runway at 150 km/h the idling engine consumes air at 50 kg/s and produces an exhaust velocity of 150 m/s.
a. What is the forward thrust of this engine?
b. What are the magnitude and direction (i.e., forward or reverse) if the exhaust is deflected 90 degree without affecting the mass flow?
c. What are the magnitude and direction of the thrust (forward or reverse) after the plane has come to a stop, with 90 degree exhaust deflection and an airflow of 40 kg/s?"
To know more about thrust,
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Answer:
a)
b)
c)
d)m
e)λ=∞
Explanation:
De Broglie discovered that an electron or other mass particles can have a wavelength associated, and that wavelength (λ) is:
with h the Plank's constant () and P the momentum of the object that is mass (m) times velocity (v).
a)
b)
c)
d)
m
e)
λ=∞