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Natasha_Volkova [10]
3 years ago
13

A driver is traveling along a straight road at the speed limit of 60 mph. After two minutes, she slows at a constant rate to a s

top at a stop light. Two minutes later, the light turns green and she accelerates at a constant rate back up to the speed limit. Three and a half minutes later, she again slows at a constant rate to a stop. After three minutes, she performs a U-turn, then accelerates at a constant rate back up to 60 mph. Two minutes later, she reaches her destination and slows at a constant rate to a stop. Assume that each period of slowing down and speeding up lasts 30 s and that the driver is initially moving in the +x- direction. Create a graph of the driver's velocity versus time that represents her trip.

Physics
1 answer:
Yuri [45]3 years ago
7 0

Explanation :

From the given information, the graph is plotted.

It is given that, a driver is traveling along a straight road at the speed limit of 60 mph. Initially, he was at point A.

After two minutes, she slows at a constant rate to a stop at a stop light. BC shows this part.

Two minutes later, the light turns green and she accelerates at a constant rate back up to the speed limit. CD shows this part.

Three and a half minutes later, she again slows at a constant rate to a stop. DE shows this part.

Hence, this is the required solution.

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What is the magnetic field inside a coil with the following conditions: 228 number of turns, 0.952 A of current and a length of
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Explanation:

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An AC circuit has an RMS voltage of 80 VAC. What's the circuit's average voltage?
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-- The RMS value of an AC waveform is (1/2)(√2) x (peak value)

So the peak value is (√2) x (RMS value)

-- The Average value of an AC waveform is (2/π) x (peak value)

So the peak value is (π/2) x (Average value).

-- So far, this is all very entertaining, but how does it help us answer the question.

Well, we found the peak value in terms of the RMS and in terms of the Average.  So we can set these equal to each other, and solve for the Average in terms of the RMS.  This sounds like such a good plan, I think I'll do it !

Peak = (√2) x (RMS value)  and  Peak also = (π/2) x (Average value).

So  (√2) · RMS = (π/2) · Average .

Divide each side by π :  (√2) · RMS / π = (1/2) · Average

Multiply each side by 2 :  Average = (2/π) · (√2) · RMS .

You said that the RMS value is 80 V, so

Average = (2/π) · (√2) · (80)

Average = (2 · √2 / π) · (80)

Average = 160√2 / π

<em>Average = 72 volts </em>.  (But be sure to read the 'gotcha' below.)


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