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Natasha_Volkova [10]
3 years ago
13

A driver is traveling along a straight road at the speed limit of 60 mph. After two minutes, she slows at a constant rate to a s

top at a stop light. Two minutes later, the light turns green and she accelerates at a constant rate back up to the speed limit. Three and a half minutes later, she again slows at a constant rate to a stop. After three minutes, she performs a U-turn, then accelerates at a constant rate back up to 60 mph. Two minutes later, she reaches her destination and slows at a constant rate to a stop. Assume that each period of slowing down and speeding up lasts 30 s and that the driver is initially moving in the +x- direction. Create a graph of the driver's velocity versus time that represents her trip.

Physics
1 answer:
Yuri [45]3 years ago
7 0

Explanation :

From the given information, the graph is plotted.

It is given that, a driver is traveling along a straight road at the speed limit of 60 mph. Initially, he was at point A.

After two minutes, she slows at a constant rate to a stop at a stop light. BC shows this part.

Two minutes later, the light turns green and she accelerates at a constant rate back up to the speed limit. CD shows this part.

Three and a half minutes later, she again slows at a constant rate to a stop. DE shows this part.

Hence, this is the required solution.

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A 0.2 kg hockey park is sliding along the eyes with an initial velocity of -10 m/s when a player strikes it with his stick, caus
babunello [35]

Answer:

The impulse applied by the stick to the hockey park is approximately 7 kilogram-meters per second.  

Explanation:

The Impulse Theorem states that the impulse experimented by the hockey park is equal to the vectorial change in its linear momentum, that is:

I = m\cdot (\vec{v}_{2} - \vec{v_{1}}) (1)

Where:

I - Impulse, in kilogram-meters per second.

m - Mass, in kilograms.

\vec{v_{1}} - Initial velocity of the hockey park, in meters per second.

\vec{v_{2}} - Final velocity of the hockey park, in meters per second.

If we know that m = 0.2\,kg, \vec{v}_{1} = -10\,\hat{i}\,\left[\frac{m}{s}\right] and \vec {v_{2}} = 25\,\hat{i}\,\left[\frac{m}{s} \right], then the impulse applied by the stick to the park is approximately:

I = (0.2\,kg)\cdot \left(35\,\hat{i}\right)\,\left[\frac{m}{s} \right]

I = 7\,\hat{i}\,\left[\frac{kg\cdot m}{s} \right]

The impulse applied by the stick to the hockey park is approximately 7 kilogram-meters per second.  

8 0
3 years ago
A block rests on a ?at plate that executes vertical simple harmonic motion with a period of 0.58s.
SVETLANKA909090 [29]

Answer:

maximum amplitude  = 0.08 m

Explanation:

Given that

Time period T= 0.58 s

acceleration of gravity g= 9.8 m/s²

We know that time period of simple harmonic motion given as

T = 2π/ω

0.58 = 2π/ω

ω = 10.83rad/s

ω=angular frequency

Lets take amplitude = A

The maximum acceleration given as

a= ω² A

The maximum acceleration should be equal to g ,then block does not separate

a= ω² A

9.8 =  10.83² A

A = 0.08m

maximum amplitude  = 0.08 m

8 0
3 years ago
Read 2 more answers
Please halp me solve this question!
Wewaii [24]

current in 3ohm resistor is 0.9

Explanation:

total

8 0
2 years ago
We divide the electromagnetic spectrum into six major categories of light, listed below. Rank these forms of light from left to
makkiz [27]

electromagnetic spectrum is consisting of many frequency range which is from gamma rays to radio waves

they are of various wavelength and different energy levels

minimum wavelength will occurs at Gamma rays

and maximum wavelength at Radio waves

the list of increasing order of wavelength is as following

Gamma rays < X rays < Ultraviolet < Visible Light < Infrared Waves < Radio Waves

so least to maximum order is

1. Gamma rays

2. X rays

3 Ultraviolet

4 Visible light

5 Infrared waves

6 Radio waves

5 0
3 years ago
.a car increases its speed from 10 m/s to 20/s in 2.5. seconds calculate it’s acceleration
Mekhanik [1.2K]

Answer:

\boxed {\boxed {\sf 4\ m/s^2}}

Explanation:

Acceleration is the rate of change of an object with respect to time. It is the change in velocity over the time.

a= \frac{v_f-v_i}{t}

The car starts at 10 meters per second and increases to 20 meters per second in 2.5 seconds.

  • v_f= 20 m/s
  • v_i= 10 m/s
  • t= 2.5 s

Substitute the values into the formula.

a= \frac{ 20 \ m/s - 10 \ m/s}{2.5 \ s }

Solve the numerator.

a= \frac{10 \ m/s}{2.5 \ s}

Divide.

a= 4 \ m/s/s

a= 4\ m/s^2

The acceleration of the car is <u>4 meters per second squared.</u>

3 0
2 years ago
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