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abruzzese [7]
3 years ago
15

City cabs charges a $2.75 pickup fee and $1.50 per mile traveled. Diego’s dare for a cross-town cab ride is $19.25. How far did

he travel in the cab
Mathematics
1 answer:
Cloud [144]3 years ago
3 0

Answer:

11 miles

Step-by-step explanation:

To find out how far he travelled we will need to start off by using the equation y =mx+b. Since the pick up fee is $2.75 we will add 2.75 to whatever our x value is making 2.75 our b value. The cab charges $1.50 per mile traveled so that will be our m value. This results in the equation being y = 1.5x + 2.75. To figure out how far he traveled we will need to plug in $19.25 into the equation. This results in the equation being: 19.25 = 1.5x + 2.75. First we will subtract both sides by 2.75. This will result in the equation being 16.5 = 1.5x. Now we will divide both sides by 1.5 to find out how far he traveled. He traveled 11 miles.

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Answer:

43.8°

Step-by-step explanation:

Applying,

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x² = y²+z²-2yxcos∅.................... Equation 1

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∅ = 43.8°

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Answer:

a) y(t) = y_{0}e^{4t} + 2. It does not have a steady state

b) y(t) = y_{0}e^{-4t} + 2. It has a steady state.

Step-by-step explanation:

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The first step is finding y_{n}(t). So:

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Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

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We have to find the eigenvalues of this differential equation, which are the roots of this equation:

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So:

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C is a constant, so (C)' = 0.

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{-4t} + 2

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