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abruzzese [7]
3 years ago
15

City cabs charges a $2.75 pickup fee and $1.50 per mile traveled. Diego’s dare for a cross-town cab ride is $19.25. How far did

he travel in the cab
Mathematics
1 answer:
Cloud [144]3 years ago
3 0

Answer:

11 miles

Step-by-step explanation:

To find out how far he travelled we will need to start off by using the equation y =mx+b. Since the pick up fee is $2.75 we will add 2.75 to whatever our x value is making 2.75 our b value. The cab charges $1.50 per mile traveled so that will be our m value. This results in the equation being y = 1.5x + 2.75. To figure out how far he traveled we will need to plug in $19.25 into the equation. This results in the equation being: 19.25 = 1.5x + 2.75. First we will subtract both sides by 2.75. This will result in the equation being 16.5 = 1.5x. Now we will divide both sides by 1.5 to find out how far he traveled. He traveled 11 miles.

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Read 2 more answers
Type the correct answer in the box. express your answer to two significant figures. a reaction between 1.7 moles of zinc iodide
irga5000 [103]

The percent yield of zinc carbonate is 5.91%.

<h3>What is chemical reaction?</h3>

The chemical reaction is the reaction between two reactants which led to the formation of products.

The products are substances which forms after reaction. The reactants are the substances which are original materials.

Given is a reaction between 1.7 moles of zinc iodide and excess sodium carbonate yields 12.6 grams of zinc carbonate.

The given balanced equation is:  Na₂CO₃ + ZnI₂ → 2NaI + ZnCO₃

From given moles of zinc iodide, the moles of zinc carbonate

1.7 moles of ZnI₂ = 1.7 moles of ZnCO₃

Molar mass of zinc carbonate is 125.38 g/mol

Theoretical yield =  1.7 moles of ZnCO₃ x  125.38 g/mol = 213.15 g  ZnCO₃

Theoretical yield is 213.15 g and the actual yield is given as 12.6 g.

percent yield = [ 12.6 g / 213.15 g  ZnCO₃ ] x 100

percent yield = 5.91%

The percent yield of zinc carbonate is 5.91%.

Learn more about chemical reaction.

brainly.com/question/22817140

#SPJ1

7 0
2 years ago
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