The best choice that you can pick will be option D.
Answer:
Option C should be correct one.
Explanation:
Negative mutations linger longer in asexual organisms. ...
Diversity is limited. ...
Population numbers can be difficult to control. ...
There can be an inability to adapt. ...
Overcrowding can be a real issue. ...
Reproduction can create competition.
Next you should analyze the data
Answer:1. Pyruvate carboxylase
2. Phosphoenol pyruvate carboxy kinase
Explanation:
The conversion of pyruvate to phosphoenol pyruvate is catalyzed by two enzymes Pyruvate carboxylase and phosphoenol pyruvate carboxy kinase
1. Pyruvate carboxylase reaction
Pyruvate in the cytoplasm enters the mitochondria. Then, carboxylase of pyruvate to oxaloacetate is catalysed by a mitochondrial enzyme, pyruvate carboxylase. It needs the co-enzymes biotin and ATP.
The oxaloacetate formed has to be transported from the mitochondrial to the cytosol because further reaction of gluconeogenesis are taking place in cytosol.
2. Phoaphoenol pyruvate carboxy kinase (PEPCK)
In the cytoplasm, PEPCK enzyme then converts oxaloacetate to phoaphoenol pyruvate by removing a molecule of CO2. GTP or ITP donates the phosphate group.
The net effect of these two reactions is the conversion of pyruvate to phoaphoenol pyruvate. This circumverts the irreversible step in glycolysis catalyzed by pyruvate kinase (step 9 if glycolysis)
Answer:
Glycolysis.
Explanation:
Glycolysis is a universal process that provides energy in the form of ATP molecules. It requires two molecules of NAD+, which are reduced to NADH during glycolysis. Thus, regeneration of NAD+ is necessary as if NAD+ is absent, glycolysis cannot be able to continue.
During anaerobic respiration (respiration in the absence of oxygen), fermentation takes place to regenerate NAD+ used in the process of glycolysis.
