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zvonat [6]
3 years ago
9

Can someone solve these for me? I have no idea what I'm doing wrong. 19 points.

Mathematics
2 answers:
VladimirAG [237]3 years ago
7 0
Okay. I think this has to do with finding the spot of "y" with "x" at a spot on the graph.
1. With "x" being at -3, we can go on the graph and see where that particular position is. When x is at -3, y is at -6. y = -6.

2. This time, we're looking for one. With x being at 1, y would be at -2, because -2 is on the y-axis, while the x-axis is still 1. y = -2.
rosijanka [135]3 years ago
6 0
The first one is 0 and the second one is -2
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so i need this for a math problem on my math subject but i forgot how to do this can you guys help me please its due soon :)
Travka [436]
Red ! Add the corresponding x coordinates and then divide by 2. Repeat for the y values
6 0
3 years ago
Read 2 more answers
Assume that an airline’s flights for miami leave every 33 minutes and flights from dallas leave every 45 minutes. If the flights
Kobotan [32]

Answer:

495

Step-by-step explanation:

To find this you have to find the LCM of the two times which in this case is 33 and 45. The LCM of those two is 495.

6 0
3 years ago
Read 2 more answers
Ramon drew boxplots to summarize the number of pages in each chapter of two books. The value of the interquartile ranges of thes
Brut [27]

Answer:

The answer is c

Step-by-step explanation:

The middle line is in the same spot

7 0
3 years ago
12. If n(A) = 14, n(B) = 15, and n(<br>AB) = 6, then n(AUB) is<br>​
motikmotik

Answer:

given n(A) = 14

n(B) = 15

n(A∩B ) = 15

Step-by-step explanation:

now we know that ,n(AUB) = n(A)+n(B)-n(A∩B)

n(AUB) = 14+15-6 = 23.Answer

3 0
3 years ago
Read 2 more answers
What is the interquartile for this set of data? 11,19,35,42,60,72,80,85,88
exis [7]

Answer:

55.5

Step-by-step explanation:

find the median - in this case it's 60

then group the upper and lower halves of the data:

(11, 19, 35, 42) 60 (72, 80, 85, 88)

now we find the medians of those sets:

35 + 19/2 = 54/2 =27

80 + 85/2 = 165/2 = 82.5

then subtract those two medians to find the interquartile:

82.5 - 27 = 55.5

4 0
3 years ago
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