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natali 33 [55]
3 years ago
10

One of your company's salesmen estimates he will drive 20,000 miles this year and each of the next two years. As the service man

ager for the company's fleet of six-cylinder compact automobiles, you are asked to determine the total costs for each of the three years. Year 1 Total Cost: $ Year 2 Total Cost: $ Year 3 Total Cost: $

Mathematics
1 answer:
grigory [225]3 years ago
4 0

Therefore, the total costs for year 1 will be $2,240, for year 2 they will be $2,040, and for year 3 they will be $2,120.

<h3><u /></h3><h3><u>Costs</u></h3>

Given that one of your company's salesmen estimates he will drive 20,000 miles this year and each of the next two years, and as the service manager for the company's fleet of six-cylinder compact automobiles, you are asked to determine the total costs for each of the three years, to determine said cost, the following calculation must be made:

  • Year 1:
  • 20000 x 0.112 = X
  • 2,240 = X

  • Year 2:
  • 20000 x 0.102 = X
  • 2,040 = X

  • Year 3:
  • 20000 x 0.106 = X
  • 2,120 = X

Therefore, the total costs for year 1 will be $2,240, for year 2 they will be $2,040, and for year 3 they will be $2,120.

Learn more about costs in brainly.com/question/4557688

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Maurinko [17]

The better buy is 18 packs for $4.99.

8 0
3 years ago
Find the equation of a line that passes through (-5,4) and us parallel to y=-6/7x+3​
irina [24]

Given:

The given equation of line is

y=-\dfrac{6}{7}x+3

To find:

The equation of line that passes through (-5,4) and is parallel to the given line.

Solution:

Slope intercept form of a line is

y=mx+b    ...(i)

where, m is slope and b is y-intercept.

We have,

y=-\dfrac{6}{7}x+3      ...(ii)

On comparing (i) and (ii), we get

m=-\dfrac{6}{7}

Slope of given line is m=-\dfrac{6}{7}.

Slope of parallel lines are same. So, slope of parallel line is m=-\dfrac{6}{7}.

The required line passes through (-5,4) with slope m=-\dfrac{6}{7}. So, the equation of line is

y-y_1=m(x-x_1)

y-4=-\dfrac{6}{7}(x-(-5))

y-4=-\dfrac{6}{7}(x+5)

y-4=-\dfrac{6}{7}x-\dfrac{30}{7}

Adding 4 on both sides, we get

y=-\dfrac{6}{7}x-\dfrac{30}{7}+4

y=-\dfrac{6}{7}x+\dfrac{-30+28}{7}

y=-\dfrac{6}{7}x-\dfrac{2}{7}

Therefore, the correct option is a.

8 0
3 years ago
What’s the answer please i don’t need work shown :)
Lady bird [3.3K]

Answer:

102

You didn't ask for work and I shall respect your wish

6 0
3 years ago
Which equation could have been used to create this function table?
patriot [66]
A  : for x = 4 y = 16 not 6 FALSE
B : for x = 4 y = 20 not 6 FALSE
C : for x = 4 y = 11 not 6 FALSE
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3 years ago
Find, from first principles,the derivative of e^tanx​
Anettt [7]

Answer:

[(sec^2)(x)]. [e^tan(x)]

Or

[e^(tan(x))]/[(cos^2)(x)].

Step-by-step explanation:

d/dx(e^tan(x))

From the low:

[(d/du)(e^u)]=[(d/du)(u)]. [ln(e)]. [e^u]

=[(sec^2)(x)]. [e^(tan(x))]. [ln(e)]

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or

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