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Marrrta [24]
3 years ago
12

What particles in an,atom determine an elements atomic number and identity?

Chemistry
2 answers:
Neko [114]3 years ago
5 0
"Number of Protons" determines it's Atomic Number & Identity 'cause 

Number of Protons = Atomic Number

Hope this helps!
ale4655 [162]3 years ago
4 0
Protons determine the atomic number and identity.
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I think it’s 4.5 x 10^9
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0.50 mol A, 0.60 mol B, and 0.90 mol C are reacted according to the following reaction
algol [13]

Reactant C is the limiting reactant in this scenario.

Explanation:

The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.

Balanced chemical reaction is:

A + 2B + 3C → 2D + E

number of moles

A = 0.50 mole

B = 0.60 moles

C = 0.90 moles

Taking A as the reactant

1 mole of A reacted to form 2 moles of D

0.50 moles of A will produce \frac{2}{1} = \frac{x}{0.50}

thus 0.50 moles of A will produce 1 mole of D

Taking B as the reactant

2 moles of B reacted to form 2 moles of D

0.60 moles of B reacted to form x moles of D

\frac{2}{2} = \frac{x}{0.6}

x = 2 moles of D is produced.

Taking C as the reactant:

3 moles of C reacted to form 2 moles of D

O.9 moles of C reacted to form x moles of D

\frac{2}{3} = \frac{x}{0.9}

= 0.60 moles of D is formed.

Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.

5 0
3 years ago
3. 78 mL of 2.5 M phosphoric acid is neutralized with 500 mL of potassium hydroxide. What is the
xenn [34]

Hence, concentration of base is 1.17 M
7 0
3 years ago
antimony(III) sulfide is reacted with excess iron. if 175.6 grams of pure antimony is produced what mass of antimony sulfide was
Ad libitum [116K]

Answer: -

The chemical formula of Antimony(III) sulfide = Sb₂S₃

Mass of Sb produced = 175.6 g

Molar mass of Sb = 121.76 g /mol

Number of moles of Sb = 175.6g / (121.76 g/mol)

= 1.44 mol

The balanced chemical equation for this reaction is

Sb₂S₃ + 3 Fe → 2 Sb + 3 FeS

From the chemical equation we see

2 mol of Sb is produced from 1 mol of Sb₂S₃

1.44 mol of Sb is produced from \frac{1 mol Sb2S3 x 1.44 mol Sb}{2 mol of Sb}

= 0.72 mol of Sb₂S₃

Molar mass of Sb₂S₃ = 2 x 121.76 + 32.06 x 3

= 339.7 g / mol

Mass of Sb₂S₃ = 0.72 mol x 339.7 g/ mol

= 244.58 g

= 244.6 g rounded off to 4 significant figures.

5 0
4 years ago
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