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Reactant C is the limiting reactant in this scenario.
Explanation:
The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.
Balanced chemical reaction is:
A + 2B + 3C → 2D + E
number of moles
A = 0.50 mole
B = 0.60 moles
C = 0.90 moles
Taking A as the reactant
1 mole of A reacted to form 2 moles of D
0.50 moles of A will produce
= 
thus 0.50 moles of A will produce 1 mole of D
Taking B as the reactant
2 moles of B reacted to form 2 moles of D
0.60 moles of B reacted to form x moles of D
= 
x = 2 moles of D is produced.
Taking C as the reactant:
3 moles of C reacted to form 2 moles of D
O.9 moles of C reacted to form x moles of D
= 
= 0.60 moles of D is formed.
Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.
Hence, concentration of base is 1.17 M
Answer: -
The chemical formula of Antimony(III) sulfide = Sb₂S₃
Mass of Sb produced = 175.6 g
Molar mass of Sb = 121.76 g /mol
Number of moles of Sb = 175.6g / (121.76 g/mol)
= 1.44 mol
The balanced chemical equation for this reaction is
Sb₂S₃ + 3 Fe → 2 Sb + 3 FeS
From the chemical equation we see
2 mol of Sb is produced from 1 mol of Sb₂S₃
1.44 mol of Sb is produced from 
= 0.72 mol of Sb₂S₃
Molar mass of Sb₂S₃ = 2 x 121.76 + 32.06 x 3
= 339.7 g / mol
Mass of Sb₂S₃ = 0.72 mol x 339.7 g/ mol
= 244.58 g
= 244.6 g rounded off to 4 significant figures.