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Helen [10]
2 years ago
10

Calculate the pH of a hydrochloride acid solution, HCl, whose hydronium ion (H3O)+ concentration is 8.29 X 10-4 M.

Chemistry
1 answer:
deff fn [24]2 years ago
5 0

Answer:

Explanation:

Calculate the pH of a hydrochloride acid solution, HCl, whose hydronium ion (H3O)+ concentration is 8.29 X 10-4 M.

Note: answer should have three significant figures

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3 years ago
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We get 1700 Tonnes of Ammonia every day. How many tonnes of 63% Nitric acid we can get?
jeyben [28]
There are 3 equations involved in manufacturing Nitric Acid from Ammonia. 

First the ammonia is oxidized:
4NH3 + 5O2 = 4NO + 6H2O

Then for the absorption of the nitrogen oxides.
2NO + O2 = N2O4

Lastly, the N2O4 is further oxidized into Nitric acid.
3N2O4 + 2H2O = 4HNO3 + 2NO

Then run stoichiometry through these equations.
The first equation produces roughly 271,722,938 grams of NO
The second equation produces roughly 416,606,944 grams of N2O4
The last equation produces roughly 380,412,294 grams of HNO3 (nitric acid)

Convert the exact number back into tons, and your answer is: <span>419.332775 tons.
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Rounded, I'm going to say that's 419.33 tons.
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Also, it seems that commercially, Nitric Acid is commonly made by bubbling NO2 into water, rather than using ammonia.
 
8 0
3 years ago
Which is a pure substance?<br> soda<br> gasoline<br> salt water<br> carbon dioxide
hram777 [196]

Answer: Carbon dioxide is a pure substance.

Explanation: A pure substance is defined when a substance has a single type of molecule. If more than 1 type of molecule is present in a substance, then it is considered as a mixture.

  • Soda is basically a mixture of water and carbon dioxide. More than 1 type of molecule is present.
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3 years ago
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How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 53.2 grams of hydrogen gas in the
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The balanced chemical reaction is:

<span>2Na + 2H2O → 2NaOH + H2
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We first use the amount of hydrogen gas to be produced and the molar mass of the hydrogen gas to determine the amount in moles to be produced. Then, we use the relation from the reaction to relate H2 to Na.

53.2 g H2 ( 1 mol / 2.02 g ) ( 2 mol Na / 1 mol H2 ) ( 22.99 g / 1 mol ) = 1210.96 g Na

1210.96 g Na ( 1 mL / 0.97 g ) = 1248.41 mL Na needed</span>
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