Answer: 44,8 l. of CO2 and 72 g. of water will be produced
Explanation:
Answer:
The correct answer is 1.21 L.
Explanation:
Based on the given information, the reaction will be,
CS2 (l) + 3Cl2 (g) ⇒ CCl4 (l) + S2Cl2 (l)
By using the standard values of the substances, the standard enthalpy of the reaction is,
ΔH° = [(-139.5) + (-58.5) – 0 – (87.3)] kJ/mol
= -285.3 kJ/mol
The amount of heat evolved for 3 moles of chlorine reacted us 285.3 kJ.
Now the number of moles of chlorine needed to react to produce 5.00 kJ is,
= 5.00 kJ × 3 mol Cl2/285.3 kJ
= 0.0526 mol Cl2
Now the volume of chlorine gas at 27degree C and 812 mmHg will be,
Volume = 0.0526 mol Cl2 × 0.0821 Latm/mol K × 300 K/ 1.07 atm
= 1.21 L
A sample 0. 100 moles of a gas is collected at at STP . 2.24 is the volume of the gas in liters.
The STP means standard temperature and pressure.
At STP,
Temperature = 0 °C =273 K
Pressure = 1 atm
We get value of volume by using ideal gas equation,
PV = nRT
- P is the pressure of the gas = 1 atm
- V is the volume occupied by the gas = ?
- n is the number of the moles = 1 mole
- T is the temperature of the gas = 273 K or 0 °C
- R universal gas constant = 8.31 J/ mole × K
Calculation,
Since, one mole of a gas occupy 22.4 L volume at STP
So, for 0.1 mole volume occupy = 22.4L × 0.1 mole/1 mole = 2.24L
To learn more about volume at STP,
brainly.com/question/1542685
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Push the pushbutton to the first stop before inserting the tip into the solution, and then put the tip in the solution tube.
Nitrogen tribromide is a chemical compound with the formula NBr3. It is extremely ... NBr3 was first prepared by reaction of bistrimethlysilylbromamine (bis(trimethylsilyl) amine bromide) ..
