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RUDIKE [14]
3 years ago
8

Is fire living or non living

Chemistry
2 answers:
Liono4ka [1.6K]3 years ago
8 0
Fire is non-living, it doesn't contain dna/rna nor does it have cells
irina1246 [14]3 years ago
6 0
Fire isn't a organism which means it's non living
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How is chemical equilibrium achieved?
just olya [345]

Answer:

Explanation:

Equilibrium is achieved in a chemical reaction when there is a steady state with no change in concentrations.

So the answer is "When the concentrations of reactants and products are constant."

7 0
2 years ago
A cube measuring 1cm x 1cm x 1cm is full of water, What is the mass of the water in the cube? (Water has a density of 1.0)
Finger [1]

d= m/v

1.0=m/1cm^3

1.0×1cm^3=m

m=1kg/cm^3

5 0
2 years ago
Hydrogen sulfide decomposes according to the following reaction, for which Kc=9.30E-8 at 700 degrees Celsius. 2 H2S(g) --> 2
Svetlanka [38]

Answer: The equilibrium concentration of H_2(g) at 700 degrees Celsius is 0.0012 M

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c


Moles of  H_2S = 0.29 mole

Volume of solution = 3.0 L

Initial concentration of H_2S = \frac{0.29mol}{3.0L}=0.097M

The given balanced equilibrium reaction is,

                    2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

         Initial conc.         0.097 M           0M          0M

At eqm. conc.    (0.097-2x) M            (2x) M   (x) M

The expression for K_c is written as:

K_c=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

K_c=\frac{(2x)^2\times x}{(0.097-2x)^2}

9.30\times 10^{-8}=\frac{(2x)^2\times x}{(0.097-2x)^2}

x=0.00060

Equilibrium concentration of [H_2]= 2x= 2\times 0.00060=0.0012M

6 0
3 years ago
Which of the following are organic compounds?
KIM [24]
I think methane and propane
3 0
3 years ago
-What is the frequency of a 5.6 x 10^10 cm wave? <br> -What is the wavelength of 0.1096 Hz wave?
bixtya [17]
The equation that we will use to solve these two questions is:
c = lambda * f where:
c is the speed f the wave
lambda is the wavelength of the wave
f is the frequency of the wave

Question 1:
we want to find f
c is assumed to be the speed of light = 3*10^8 m/sec
lambda = 5.6 * 10^10 cm = 560 * 10^6 meters
Substitute in the equation to get f as follows:
3*10^8 = 560*10^6*f
f = (3*10^8) / (560*10^6) = 0.5357 Hz

Question 2:
we want to find lambda
c is assumed to be the speed of light = 3*10^8 m/sec
f is given as 0.1096 Hz
Substitute in the equation to get lambda as follows:
3*10^8 = lambda * 0.1096
lambda = (3*10^8) / (0.1096) = 2.737226*10^9 meters
3 0
3 years ago
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