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2 years ago

Mg + 2AgNO3 -> 2Ag + Mg(NO3)2

Chemistry

1 answer:

9966 [12]2 years ago

5 0

Answer:

Explanation:

We'll assume there is an excess of silver nitrate, so that all 12.0 moles of the magnesium (Mg) will react.

The balanced equation tells us we'll obtain 2 moles of Ag for every 1 mole of magnesium, for a molar ratio of 2/1.

Starting with 12.00 moles Mg, we would therefore hope to find twice that, or 24.00 moles of Ag.

To convert to grams, find the molar mass of Ag from the periodic table.

Ag has a molar mass of 107.9 (to 4 sig figs) grams/mole.

(24.00 moles)*(107.9 grams/mole) = 2590 grams (4 sig figs)

Hands off, it's mine.

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What is the amount of solute required if the solution is 50 ml and the solvent is 35 ml. Solve and explain

e-lub [12.9K]

Answer:

15 mL of the solute

Explanation:

From the question given above, the following data were obtained:

Solution = 50 mL

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Solute =?

Solution is simply defined as:

Solution = solute + solvent

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2 years ago

A 1.85 kg textbook is sitting on a bookshelf 2.23 m above the floor. How much potential energy does it have?

neonofarm [45]

Answer:

$\boxed {\boxed {\sf 40.4299 \ Joules}}$

Explanation:

Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.

$PE= m \times g \times h$

The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.

m= 1.85 kg
g= 9.8 m/s²
h= 2.23 m

Substitute the values into the formula.

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Multiply the first 2 numbers together.

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Multiply again.

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1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J

$PE= 40.4299 \ J$

The textbook has <u>40.4299 Joules of potential energy.</u>

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