Your answer would be respiration. This would be your answer because, plants take in carbon dioxide, and animals, including humans, breath oxygen. I hope this had helped you out.
Answer:
Electron geometry- Tetrahedral
Molecular geometry- Bent
Bond angle- <<109.5°
Explanation:
According to the Valence Shell Electron Pair Repulsion (VSEPR) Theory, the shape of a molecule depends on the number of electron pairs present bon the central atom of the molecule. The electron pairs orient themselves as far apart in space as possible to minimize repulsion between electron pairs.
However, the repulsion between all electron pairs is not the same. Lone pairs cause more repulsion around the central atom than bond pairs. Hence lone pairs tend to distort the molecular structure away from that predicted on the basis of Valence Shell Electron Pair Repulsion Theory.
Considering XY2Z2, there are four electron domains, two bond pairs with bonding groups at 180° apart and two lone pairs. Based on VSEPR theory, a tetrahedral shape is expected with a bond angle of about 109°.
The presence of two lone pairs distorts the observed molecular geometry to a bent shape with bond angle <<109°, hence the answer above.
Release larger amouts of energy
Answer:
4.16x10⁻³m
Explanation:
Molality is defined as the ratio between moles of a solute, in this case glucose, and kg of solvent.
As there are 100g of solvent, <em>the kg are 0.1. </em>Thus, we only need to calculate from the mass of glucose its moles to solve the molality of the solution.
<em>Moles glucose:</em>
There are 75mg = 0.075g of glucose. To conver mass to moles it is necessary molar mass.
Molar mass glucose:
6C = 12.01g/mol*6 = 72.06g/mol
12H = 12*1.008g/mol = 12.10g/mol
6O = 6*16g/mol = 96g/mol
72.06 + 12.10 + 96 = 180.16g/mol
Moles of 0.075g of glucose:
0.075g * (1 mol / 180.16g) =
4.16x10⁻⁴ moles of glucose
<em>Molality of the solution:</em>
4.16x10⁻⁴ moles of glucose / 0.1kg of solvent =
<h3>4.16x10⁻³m</h3>
The correct answer is e. 3.57×10³
Al³+(aq) + 3e→AL(s)
4.00g of AL=4g/26.98 g/mol= 0.1483 mol
t=znF/1 where t is time in seceonds.
Z= valency number of ions of the substance or electrons which are transferred per ion
F= Faraday's constant
I = electric current in'A'CA C/s
t=(3×0.1483 mol ×96485 C/mol) /12(C15)
t=3577 second = 3.5 ×10³s
