Answer:
a) 10,500 big cats
b) 13,401 big cats
c) 33 years
Step-by-step explanation:
Hi, to answer this question we have to apply an exponential growth function:
A = P (1 + r) t
Where:
p = original population
r = growing rate (decimal form; 5/100= 0.05)
t= years
A = population after t years
Replacing with the values given:
a) At 2005, 1 year passed since 2004 (t=1)
A = 10,000 (1+ 0.05)^1
A = 10,500 big cats
b)
At 2010, 6 years passed since 2004 (2010-2004= 6)
A = 10,000 (1+ 0.05)^6
A = 13,401 big cats
c)
50,000 < 10,000 (1+ 0.05)^t
Solving for t:
50,000/10,000 < 1.05^t
5 < 1.05^t
log 5 < log 1.05^t
log 5 < t ( log 1.05)
log 5 / log 1.05 < t
32.9 years < t
33 years = t
Feel free to ask for more if needed or if you did not understand something.
