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lana66690 [7]
4 years ago
14

Suppose you are filling an Olympic-size swimming pool at a rate of 16,000 gallons per hour. The pool will hold a total of 648,00

0 gallons of water. You've been filling the pool for 12 hours. How many more hours until the pool is full?
Mathematics
1 answer:
STALIN [3.7K]4 years ago
3 0
I think you would divide 16,000 gallons per hour by, 12 hours.
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In an auditorium, a charity show is conducted in order to raise at least $3,750. The auditorium can accommodate up to 180 specta
Maksim231197 [3]

Answer:

See explanation

Step-by-step explanation:

Let x,\ x\ge 0 be the number of students and y,\ y\ge 0 be the number of adults on the show.

1. Tickets cost $15 for students, so x student tickets cost $15x.

Tickets cost $25 for adults, so y adult tickets cost $25y.

Total cost of all tickets is $(15x + 25y).

The charity show is conducted in order to raise at least $3,750, thus

15x+25y\ge 3,750

2. The auditorium can accommodate up to 180 spectators, hence

x+y\le 180

3. We get the system of inequalities:

\left\{\begin{array}{l}x\ge 0\\y\ge 0\\x+y\le 180\\15x+25y\ge 3,750\end{array}\right.

Plot all solutions sets to each inequality and the common region is the solution set to the system of inequalities. This region is not empty, so the charity will reach its goal. For example, if they sell 50 students tickets and 125 adult tickets, they will raise \$(15\cdot 50+25\cdot 125)=\$3,875

8 0
3 years ago
A rectangular prism has a length of 1514 centimeters, a width of 8 centimeters, and a height of 214 centimeters. Enter the volum
vichka [17]
Hewwo dere fello citizen, The answer is 274 1/2cm! Rate me five stars and meow! :3
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4 years ago
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How would you translate this situation below into an algebraic expression?
Natasha2012 [34]
Dime value: $0.10
Nickel value: $0.05

For this word problem, you are asked to create an algebraic expression (an equation) for the unknown variables. 

Now, we know that a dime is worth $0.10 or 10 cents and a nickel is worth $0.05 or 5 cents. So, all you would have to do is create an equation that takes those values into account. 
5n + 10d

Your algebraic expression would be B. 5n + 10d

I hope this helps!
5 0
3 years ago
Graph for f(x)=6^6 and f(x)=14^x
zlopas [31]

Graph Transformations

There are many times when you’ll know very well what the graph of a

particular function looks like, and you’ll want to know what the graph of a

very similar function looks like. In this chapter, we’ll discuss some ways to

draw graphs in these circumstances.

Transformations “after” the original function

Suppose you know what the graph of a function f(x) looks like. Suppose

d 2 R is some number that is greater than 0, and you are asked to graph the

function f(x) + d. The graph of the new function is easy to describe: just

take every point in the graph of f(x), and move it up a distance of d. That

is, if (a, b) is a point in the graph of f(x), then (a, b + d) is a point in the

graph of f(x) + d.

As an explanation for what’s written above: If (a, b) is a point in the graph

of f(x), then that means f(a) = b. Hence, f(a) + d = b + d, which is to say

that (a, b + d) is a point in the graph of f(x) + d.

The chart on the next page describes how to use the graph of f(x) to create

the graph of some similar functions. Throughout the chart, d > 0, c > 1, and

(a, b) is a point in the graph of f(x).

Notice that all of the “new functions” in the chart di↵er from f(x) by some

algebraic manipulation that happens after f plays its part as a function. For

example, first you put x into the function, then f(x) is what comes out. The

function has done its job. Only after f has done its job do you add d to get

the new function f(x) + d. 67Because all of the algebraic transformations occur after the function does

its job, all of the changes to points in the second column of the chart occur

in the second coordinate. Thus, all the changes in the graphs occur in the

vertical measurements of the graph.

New How points in graph of f(x) visual e↵ect

function become points of new graph

f(x) + d (a, b) 7! (a, b + d) shift up by d

f(x) Transformations before and after the original function

As long as there is only one type of operation involved “inside the function”

– either multiplication or addition – and only one type of operation involved

“outside of the function” – either multiplication or addition – you can apply

the rules from the two charts on page 68 and 70 to transform the graph of a

function.

Examples.

• Let’s look at the function • The graph of 2g(3x) is obtained from the graph of g(x) by shrinking

the horizontal coordinate by 1

3, and stretching the vertical coordinate by 2.

(You’d get the same answer here if you reversed the order of the transfor-

mations and stretched vertically by 2 before shrinking horizontally by 1

3. The

order isn’t important.)

74

7:—

(x) 4,

7c’

‘I

II

‘I’

-I

5 0
3 years ago
6 millones restado 300¿
Brut [27]

Step-by-step explanation:

6,000,000-300=5,999,700

4 0
3 years ago
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