answer = the elder bother is 17 and the younger one is 15
constructive odd integers= 15 and 17
17×15= 255
255+38 = 293
Square root of 293 = 17
Answer:
4/5 or 0.8
Step-by-step explanation:
Answer:
<h3>
1) 7x - 5
</h3><h3>
2) 9y - 18
</h3><h3>
3) 0.5n + 4n
</h3><h3>
4) 2(w³+23)</h3><h3>
Step-by-step explanation:</h3>
1)
The product of seven and a number x: 7·x = 7x
<u>Five less than the product of seven and a number x:</u>
<h3>
7x - 5
</h3>
2)
nine times a number y: 9·y = 9y
<u>The difference of nine times a number y and eighteen:</u>
<h3>
9y - 18
</h3>
3)
half a number n: 0.5n
four times the number: 4·n = 4n
<u>Half a number n increased by four times the number:</u>
<h3>
0.5n + 4n
</h3>
4)
a number w cubed: w³
the sum of a number w cubed and twenty-three: w³+23
<u>Twice the sum of a number w cubed and twenty-three:</u>
<h3>2(
w³+23)</h3>
For this case we propose a system of equations. We have to:
x: Let the variable that represents the number of dimes
y: Let the variable that represents the number of quaters
We know that:
One dime equals 10 cents, $0.10
A quater equals 0.25 cents, $0.25
According to the statement we have:
We multiply the first equation by -0.10:
We have the following equivalent system:
We add the equations:
Approximately 3 quater coins
And two dimes
Answer:
3 quater
2 dimes
