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True [87]
3 years ago
9

I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find

the measure of each arc. For each arc, write two or more complete sentences explaining which theorem or postulate you used to find your answer. Include your equations and calculations in your final answer. find mRP, MQS, MPQR, and MRPQ

Mathematics
1 answer:
netineya [11]3 years ago
6 0

Answer:

see below

Step-by-step explanation:

mROP= 125°

mSOQ= mROP= 125°

mROQ=mPOS= 180°-125°= 55°

<u>Sum of measures of all arcs in the circle= 2π</u>

mRP= mQS=2π*125/360=25/36π

mQR=mPS=2π*55/360=11/36π

mPRQ= half circle= 2π/2= π

mRPQ= 2π-mQR= 2π- 11/36π= 61/36π

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DENIUS [597]
-9v-6+7v=6
-2v-6=6
-2v=6+6
-2v=12
v=-6
8 0
3 years ago
4) How much interest does a $276 investment earn at 9% over seven<br> years?"<br> 2
Mice21 [21]

Answer: 24.84

Step-by-step explanation: 276%of 9 is 24.84

4 0
3 years ago
1 find the area in square cm of a square whose side is
lara [203]
For question 1:

Part i)

2.6 x 2.6 = 6.76 cm squared

No unit conversions needed

Part ii)

1.2 dm = 1.2 / 1000000 = 0.0000012 cm

0.0000012 x 0.0000012 = 0.00000000000144 cm squared

Question 2:

16.5dm = 16.5/ 1000 = 0.0165 m

0.0165 x 0.0165 = 0.00027225 m squared

I hope this has helped
3 0
3 years ago
Read 2 more answers
I need help with no.7
ziro4ka [17]

Answer:

  (a) 315°

  (b) 3°

  (c) 238°

Step-by-step explanation:

Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.

<h3>(a)</h3>

The bearing of P from R is 180° different from the bearing of R from P it will be ...

  135° +180° = 315° . . . . bearing of P from R

__

<h3>(b)</h3>

The bearing of Q from R is 48° more than the bearing of P from R, so is ...

  315° +48° = 363°, or 3° . . . . bearing of Q from R

__

<h3>(c)</h3>

The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...

  180° -48° -55° = 77°

The bearing of Q from P is 77° less than the bearing of R from P, so is ...

  135° -77° = 58°

As above, the reverse bearing from Q to P is ...

  58° +180° = 238° . . . . bearing of P from Q

8 0
2 years ago
Can someone explain this? :)
Alchen [17]

I'll do part (a) to get you started.

The angle 'a' pairs up with the 123 degree angle as a corresponding angle pair. Due to the parallel lines, the corresponding angles are congruent. Therefore a = 123.

We also see that b = 123 as well since a = b (they are vertical angles).

Notice how angle c is adjacent to the 123 degree angle. These two angles form a straight line, so they must add to 180 degrees.

c+123 = 180

c = 180-123

c = 57

-------------------------

To summarize, we have these three angles

a = 123

b = 123

c = 57

6 0
3 years ago
Read 2 more answers
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