Ask question

Ask question

All categories

3 years ago

9

I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find

the measure of each arc. For each arc, write two or more complete sentences explaining which theorem or postulate you used to find your answer. Include your equations and calculations in your final answer. find mRP, MQS, MPQR, and MRPQ

1 answer:

netineya [11]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

mROP= 125°

mSOQ= mROP= 125°

mROQ=mPOS= 180°-125°= 55°

<u>Sum of measures of all arcs in the circle= 2π</u>

mRP= mQS=2π*125/360=25/36π

mQR=mPS=2π*55/360=11/36π

mPRQ= half circle= 2π/2= π

mRPQ= 2π-mQR= 2π- 11/36π= 61/36π

You might be interested in

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

3 years ago

What is required in aerobic respiration?<br>

likoan [24]

O2, or Oxygen, and C6H12O6, or glucose.

6 0

2 years ago

For the function f(x)=|x−7|−4, evaluate f(x+1).

GarryVolchara [31]

Answer:

$\displaystyle{f(x+1)=|x-6|-4}$

Step-by-step explanation:

To evaluate $\displaystyle{f(x+1)}$ , substitute $\displaystyle{x}$ to $\displaystyle{x+1}$ so we should have:

$\displaystyle{f(x+1) = |x+1-7|-4}$

Evaluate the expression and finally, we have:

$\displaystyle{f(x+1)=|x-6|-4}$

Learn More

brainly.com/question/27923727 - How to find inverse and value of function

6 0

2 years ago

-3x - y = 0 and -8x +5y=7

andrezito [222]

Answer:

-23x = 7

Step-by-step explanation:

-3x - y =0

×5. ×5 ×5

-15x -5y = 0

-8x +5y = 7

-15x -5y -0

-23x = 7

8 0

3 years ago

Please help !!!! will mark brainliest

GarryVolchara [31]

Answer:

the answer is D :))) hope you pass this

3 0

3 years ago