What is the solution set to three parallel lines
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Please see the explanation of this question to see procedure for the dilation of the triangle ABC and the image attached below to know the result.
<h3>How to generated a resulting triangle by transformation rules</h3>
In this question we must apply a kind of <em>rigid</em> transformation known as dilation. A dilation of a point around a point of reference is defined by the following operation:
P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)] (1)
Where:
- O(x, y) - Point of reference
- k - Dilation factor
- P(x, y) - Original point
- P'(x, y) - Resulting point
Let assume that the point P is the origin of a <em>rectangular</em> system of coordinates. Then, the coordinates of the three vertices of the triangle ABC respect to the origin are: A(x, y) = (- 1, 2), B(x, y) = (- 1, - 1), C(x, y) = (2, 0).
Then, the vertices of the resulting triangle A'B'C' are, respectively:
A'(x, y) = (0, 0) + 3 · [(- 1, 2) - (0, 0)]
A'(x, y) = (- 3, 6)
B'(x, y) = (0, 0) + 3 · [(- 1, - 1) - (0, 0)]
B'(x, y) = (- 3, - 3)
C'(x, y) = (0, 0) + 3 · [(2, 0) - (0, 0)]
C'(x, y) = (6, 0)
Finally, we draw the resulting triangle with the help of a graphing tool.
To learn more on dilations: brainly.com/question/13176891
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