It should be 1000x which is the total magnification of the whole thing... I believe. Would you happen to be doing a microscope quiz
Answer:
these differentiate as a result of signaling mechanisms. ... The daughter cells divides and after each division it becomes more specialized. When it reaches a mature cell type downstream (for example, becomes a red blood cell) it will no longer divide.
Answer:
1) in the direction of the applied force
2)when the movement is not in the direction of the applied force it is not work. But if a component, or part of the motion is in the direction of the applied force it is work.
3)Joules/sec
4)Force/displacement
6)Wedges and lever
5)conduction
6)radiation
7)there is no heat flow
8)The average kinetic motion of the particles increases, there is more thermal energy
9)The average kinetic motion of the particles decreases, there is less thermal energy
10)transverse wave
11) sound waves
12)they transfer energy through oscillations in matter
13)the speed of the pitched baseball
14)to detect speed and direction of blood flow
15)green and violet are reflected and red is absorbed
16)visible light
17)as heat
18)infrared light/infrared energy
19)reflection
20) yes, the forces emitted by having the same charge repells them.
21)the flow of electrons
22)You open the circuit and the electrons can't flow
23)You closed the circuit and the electrons can flow
24)I think you meant bipolar, this means 2 poles
Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>
