Answer:
1.63425 × 10^- 18 Joules.
Explanation:
We are able to solve this kind of problem, all thanks to Bohr's Model atom. With the model we can calculate the energy required to move the electron of the hydrogen atom from the 1s to the 2s orbital.
We will be using the formula in the equation (1) below;
Energy, E(n) = - Z^2 × R(H) × [1/n^2]. -------------------------------------------------(1).
Where R(H) is the Rydberg's constant having a value of 2.179 × 10^-18 Joules and Z is the atomic number= 1 for hydrogen.
Since the Electrons moved in the hydrogen atom from the 1s to the 2s orbital,then we have;
∆E= - R(H) × [1/nf^2 - 1/ni^2 ].
Where nf = 2 = final level= higher orbital, ni= initial level= lower orbital.
Therefore, ∆E= - 2.179 × 10^-18 Joules× [ 1/2^2 - 1/1^2].
= -2.179 × 10^-18 Joules × (0.25 - 1).
= - 2.179 × 10^-18 × (- 0.75).
= 1.63425 × 10^- 18 Joules.
E since its a physical model i.e. you can touch and feel the model :)
Answer:
3.31 atm.
Explanation:
- Gay-Lussac's law states that for a given mass and constant volume of an ideal gas, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.
∵ P α T.
<em>∴ P₁T₂ = P₂T₁.</em>
P₁ = 3.00 atm, T₁ = 20.0 °C + 273.15 = 293.15 K.
P₂ = ??? atm, T₂ = 50.0 °C + 273.15 = 323.15 K.
<em>∴ P₂ = (P₁T₂)/T₁</em> = (3.00 atm)( 323.15 K)/(293.15 K) = <em>3.307 atm ≅ 3.31 atm.</em>
Bismuth(III) Sulfide is a brownish powder that is soluble in acids.
