Answer:
The volume of mercury-contaminated water that has to be consumed to ingest 0.100 g mercury is 2.50 × 10⁴ l
Explanation:
Hi there!
First, let´s convert 0.100 g to mg:
0.100 g · (1000 mg/1 g) = 100 mg
The contaminated water has 0.004 mg per liter, then, we have to find the volume of water that contains 100 mg of mercury:
100 mg · (1 l / 0.004 mg) = 2.50 × 10⁴ l
Then, the volume of mercury-contaminated water ( at a concentration of 0.004 mg/l) that has to be consumed to ingest 0.100 g mercury is 2.50 × 10⁴ l
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Answer:
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