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algol [13]
2 years ago
12

which factors have the greatest effect on the rate of a chemical reaction between AgNO3(aq) and Cu(s)?

Chemistry
1 answer:
Kaylis [27]2 years ago
8 0
The rate of reaction of uncatalyzed reactions is mainly dependent on two factors:
1) Concentration of reactants
The greater the concentration of reactants that is present, the faster the reaction will take place
2) Temperature
Due to increased collisions of reactant molecules, elevating the temperature of a reaction mixture increases the rate of reaction
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Wouldnt you find that on the grid or the table
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In the diagram of a transverse wave shown, what does P represent?
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L is amplitude M is wavelength and P is frequency
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Zn +
saul85 [17]

Answer:

1. Theoretical yield = 2.03g

2. Actual yield 1.89g

Explanation:

Let us write a balanced equation. This is illustrated below:

Zn + 2HCI —> ZnCl2 + H2

Molar Mass of HCl = 1 +35.5 = 36.5g/mol

Mass of HCl from the balanced equation = 2 x 36.5 = 73g

Molar Mass of H2 = 2x1 = 2g/mol

1. From the equation,

73g of HCl produced 2g of H2.

Therefore, 74g of HCl will produce = (74 x 2)/73 = 2.03g

Therefore, theoretical yield = 2.03g

2. %yield = 93%

Theoretical yield = 2.03g

Actual yield =?

%yield = Actual yield /Theoretical yield x100

Actual yield = %yield x theoretical yield

Actual yield = 93% x 2.03 = (93/100)x2.03 = 1.89g

Actual yield =1.89g

4 0
3 years ago
Select the correct answer. What happens when an electron absorbs energy? A. The electron moves from a lower energy orbital to a
umka2103 [35]
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The electron absorbs energy from specific wavelength then moving from a lower energy orbital to a higher energy orbital.
3 0
2 years ago
Find the horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40m/s​
vfiekz [6]

To Find :

The horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40 m/s​.

Solution :

The horizontal range of a projectile is given by :

R = \dfrac{u^2 sin 2\theta}{g} ( Here, g is acceleration due to gravity = 10 m/s² )

Putting all value in above equation :

R = \dfrac{40^2 \times sin (2 \times 15)}{10} \ m\\\\R = \dfrac{1600 \times 1}{2\times 10} \ m\\\\R = 80 \ m

Therefore, the horizontal range of projectile is 80 m.

4 0
3 years ago
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