Answer:
pH at the equivalence point for titration of HF and HCl will be basic and neutral respectively.
Explanation:
pH at equivalence point depends on hydrolysis equilibrium of conjugated base present in mixture.
Neutralization reaction: ![HF+OH^{-}\rightleftharpoons F^{-}+H_{2}O](https://tex.z-dn.net/?f=HF%2BOH%5E%7B-%7D%5Crightleftharpoons%20F%5E%7B-%7D%2BH_%7B2%7DO)
Hence, at equilibrium,
is present in mixture.
Hydrolysis reaction: ![F^{-}+H_{2}O\rightleftharpoons HF+OH^{-}](https://tex.z-dn.net/?f=F%5E%7B-%7D%2BH_%7B2%7DO%5Crightleftharpoons%20HF%2BOH%5E%7B-%7D)
Here HF is an weak acid and
is a strong base, So, resultant pH of the solution will be basic.
Neutralization reaction: ![HCl+OH^{-}\rightleftharpoons Cl^{-}+H_{2}O](https://tex.z-dn.net/?f=HCl%2BOH%5E%7B-%7D%5Crightleftharpoons%20Cl%5E%7B-%7D%2BH_%7B2%7DO)
Hence, at equilibrium,
is present in mixture.
Hydrolysis reaction: ![Cl^{-}+H_{2}O\rightleftharpoons HCl+OH^{-}](https://tex.z-dn.net/?f=Cl%5E%7B-%7D%2BH_%7B2%7DO%5Crightleftharpoons%20HCl%2BOH%5E%7B-%7D)
Here HCl is a strong acid and
is a strong base, So, resultant pH of the solution will be neutral.
Answer:
By electroplating
Explanation:
The metal which requires to be protected from rust is connected to the anode while a lower metal in the series is connected to the cathode, the a complete circuit is made and current is passed through the circuit there by resulting to the coating of the metal at the anode.
3:6:2 is the correct answer