Answer:
If an inhibitory synapse fires at the same time and at the same distance from the initial segment as an excitatory synapse of the same intensity there will be no changes in the potential in the firing zone.
Explanation:
Under normal conditions, the transmembrane potential depends on the ionic charges present in the intracellular and extracellular spaces. The extracellular space load is usually positive and in the cytoplasm is negative.
- <u>Depolarization</u> occurs by opening ion channels that allow sodium to enter the cell, making the intracellular space more positive.
- An opening of potassium channels releases this ion to the extracellular space, leading to <u>hyperpolarization</u>.
An excitatory synapse is one capable of depolarizing a cell and boosting the production of action potential, provided it is capable of reaching the threshold of said potential.
On the other hand, an inhibitory synapse is able to hyperpolarize the cell membrane and prevent an action potential from originating, so that they can inhibit the action of an excitatory synapse.
The interaction between two synapses, one excitatory and one inhibitory, -called synapse summation- will depend on the strength that each of them possesses. In this case, the intensity of both synapses being the same, there will be no changes in the membrane potential in the firing zone.
Learn more:
Excitatory and inhibitory postsynaptic potentials brainly.com/question/3521553
Answer:
<h2>The Cornea in the ear</h2>
Explanation:
is the parts of the human body that get oxygen directly from the air and not from the blood
<span>The first law of thermodynamics is follows the quantity dQ = dW + dU where Q is the heat flow, W is the work and U is the internal energy. Only the internal energy is a state function where it means that it does not follow a specific path to arrive at a certain number. Whereas the work and heat are not state functions and they follow a specific path or process in order to arrive at a certain number. An example would be if y</span>ou are given 2,380 J of energy to do work as 12,900 J and you are to find the internal energy. Apply the equation above:
Q = U + W
2,380 J = U + 12,900 J
U = 15,280J.
Answer:
Transcription begins at a gene's promoter, a specific sequence of DNA that acts as a "start" signal for a gene that is to be transcribed. Transcription ends at a sequence of bases that acts as a "stop" signal.
Explanation:
They are only present in plant cells an they are green pigment and where photosynthesis take place
