Ok, colour blindness and blood type are independently assorting traits, that means that having one does not affect having the other, the question even tells you that the traits are on different chromosomes.
<span>To answer your question we'll have to calculate the probability of both traits in the child and then multiply them together to get the overall probability of both being present in the child. </span>
<span>Let's start with blood type: there are four types of blood type: AB, A, B and O. Blood type is determined by what protein each chromosome codes for: so if one chromosome is I^A and codes for A type protein, while the other is I^B and codes for B type protein, then the overall blood type will be AB. O blood type is recessive, it doesn't code for any protein at all and is given the symbol i. </span>
<span>Since both parents are type A and their first child is type O, you know that both parents are heterozygous for blood type A, meaning that one chromosome they have is I^A and the other is type or or i. For a child to be blood type O, each parent has to give their type O chromosome to the child. There is a 1/2 chance that one parent will give the recessive O chromosome, so for both parents to give their recessive allele the probability is 1/2 * 1/2 = 1/4 </span>
<span>Colour blindness is an X-linked condition, that means that women can be carriers but not manifest the colour blindness because they have one "good" X chromosome which masks the recessive colourblindness gene on the other X. The father cannot have a colourblindness gene or else he'd be colourblind himself, since he's only got 1 X-chromosome. Because dad has healthy eyesight, any girls he has will have healthy eyesight too, since his X will always be healthy and mask the X from mom if she happens to give the recessive colourblind gene. So the probability that the girl will have normal vision is 1/1. </span>
<span>However, it is not a given that the baby born will be a girl, there's a 50/50 chance that it'll be one or the other sex, so we need to consider the probability involved with the child being a girl. this probability is 1/2. </span>
<span>So now we multiply all our probabilities together to calculate what the chances of a normal visioned, type O blood typed girl is: </span>
<span>Normal vision (1) * blood type O (1/4) * girl baby (1/2) = 1/8 </span>
<span>So your probability is 1/8! </span>
<span>Hope this helps :)</span>
The correct option is (D) iteroparous; K -selected
Iteroparous organisms are the organisms that reproduce multiple times.
<h3>
What is Semelparity and Iteroparity?</h3>
- Semelparity and iteroparity are the two different reproductive strategies available to living beings.
- Iteroparous species have multiple reproductive cycles throughout their lifetimes, while semelparous species have just one reproductive cycle before they die.
- Death that occurs after reproduction is part of a bigger strategy in really semelparous animals that also entails maximizing reproduction at the expense of future survival.
- There will always be some iteroparous individuals who die between their first and second reproductive episodes, but unless they exhibit symptoms of a state of programmed death after reproduction, they are not termed semelparous.
Learn more about the Iteroparity with the help of the given link:
brainly.com/question/13046555
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The law of conservation of energy states that e<span>nergy cannot be destroyed. Energy can only transform from one another.
Answer: B </span>✅ <span>
Hope that helps. -UF aka Nadia</span>
A) over time finches on the island adapted and evolved as a result of competition over resources. It was one of Darwin's original focuses for his Theory of Evolution
