All categories

3 years ago

What is the solution for this equation? 8(7-(6x- 6) )+ 6x = 0

2 answers:

7 0

Distribute 8 =
= 56 - (48x - 48) + 6x = 0
Distribute the minus =
= 56 - 48x + 48 + 6x = 0
Add like terms =
= 42x + 104 = 0
Solve for x =
= 42x = -104
= x = 2.48

Eddi Din [679]3 years ago

6 0

Im pretty sure that
x=3

You might be interested in

Pls help with this question

Andreyy89

Answer:

7.01, 10, 7.1, 12, 7.001, 8, 15

Step-by-step explanation:

Those numbers are all greater than 7

7 0

3 years ago

What is 3k-14=3(k-5)+1 ?

stealth61 [152]

Answer:

True

Step-by-step explanation:

3k-14=3(k-5)+1

3k-14=3k-15+1

3k-3k=14-15+1

0=14-15+1

-14=-15+1

-14=-14

8 0

3 years ago

Yeahhh if you could help that would be great

stellarik [79]

Answer: what wrong

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

I need help ASAP!!

Viktor [21]

Answer:

$\frac{64}{49}$

Step-by-step explanation:

As we can see the given expression as three complex parts and all are being multiplied.

Lets simplify each part separately and then multiply all of them in the end

Part1

$(\frac{8.4.2}{8.7})^{2}$

Cancelling 8 in numerator with 8 in denominator

$(\frac{4.2}{7})^{2}$

$(\frac{8}{7})^{2}$

$\frac{64}{49}$

Part2

$(\frac{8^{0} }{7^{-3} })^{3}$

simpliying

$(\frac{1}{7^{-3} })^{3}$

$({7^{3} })^{3}$

$7^{9}$

Part3

Third part is $7^{-9}$ , and it does not need to be further simplified

Now multiplying all the three parts

$\frac{64}{49}.7^{9}.7^{-9}$

$\frac{64}{49}.7^{9-9}$

$\frac{64}{49}.7^{0}$

$\frac{64}{49}.1$

$\frac{64}{49}$

So our final answer is $\frac{64}{49}$

5 0

3 years ago

Brainliest + Points!

AysviL [449]

I believe the correct answer would be B. Down payment

Your welcome

5 0

3 years ago