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3 years ago

Find the output, kkk, when the input, ttt, is -7−7minus, 7. k = 10t-19k=10t−19

Mathematics

2 answers:

Sati [7]3 years ago

8 0

The output k at input t = -7 is -89

Step-by-step explanation:

In order to find the value of a expression on given number, we put the number in given expression in place of independent variable

So,

Given expression is:

$k = 10t-19$

It is given that the value of t has to be -7

so putting t=-7 in the expression

$k = 10(-7)-19\\k = -70-19\\k = -89$

Hence,

The output k at input t = -7 is -89

Keywords: Expressions, input, output

Learn more about expressions at:

#LearnwithBrainly

vlada-n [284]3 years ago

6 0

Answer:

The output k at input t = -7 is -89

Step-by-step explanation:

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3 years ago

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Answer:

We conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

Step-by-step explanation:

Given the radical expression

$\sqrt{\left(-81\right)x^2}$

simplifying the expression

$\sqrt{\left(-81\right)x^2}$

Remove parentheses: (-a) = -a

$\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}$

Apply radical rule: $\sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=\sqrt{-1}\sqrt{81x^2}$

Apply imaginary number rule: $\sqrt{-1}=i$

$=i\sqrt{81x^2}$

Apply radical rule: $\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt{81}i\sqrt{x^2}$

$=9i\sqrt{x^2}$

Apply radical rule: $\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=9ix$

Therefore, we conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

7 0

3 years ago

2. What are the next two terms of the following sequence?-2,4,-8, 16, ...

Marat540 [252]

Answer:

Step-by-step explanation:

$-2\\(-2)(-2)=4\\(-2)(4)=-8\\(-2)(-8)=16\\-----------------\\(-2)(16)=-32\\(-2)(-32)=64\\\vdots$

Each next term is created by multiplying the previous term by (-2).

3 0

3 years ago

Read 2 more answers

A line passes through the point (–6, –2), and its y-intercept is (0, 1). What is the equation of the line that is perpendicular

Mama L [17]

The slope of first line is m 1= ( 1 - 0 ) / ( - 2 - ( - 6 ) );
m = 1 / 4 ;
Because the second line is perpendicular to the first line, m2 * m1 = - 1 ;
m2 * ( 1 / 4 ) = -1;
m2 = - 4 ;
The equation of the second line is : y - 3 = ( - 4 )( x - 2 );
y - 3 = -4x + 8 ;
y = -4x + 11.

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3 years ago