Join the centre O to the chord (let it be MN) & let OH be the perpendicular to the chord
OH bisects MN into 2 equal parts (each one is x/2)
OMH is a right triangle with one side =8, the second leg =x/2 & the hypotenuse = 12 (Radius)
Apply Pythagoras:
12² = 8² +(x/2)² ==>144=64 + x²/4 ==> x²=4(144-64) =320
x²=320==> x=√320 =17.88 ≈17.9
Answer:
x = 28
Step-by-step explanation:
From the figure attached,
AC ≅ FH [Given]
BC ≅ GH [Given]
AB ≅ FG [Given]
ΔABC ≅ ΔFGH [By SSS property of congruence]
Since, m∠A + m∠B + m∠C = 180°
50° + 69° + m∠C = 180°
119° + m∠C = 180°
m∠C = 180° - 119°
m∠C = 61°
m∠C = m∠H [Since, ΔABC ≅ ΔFGH]
(2x + 5)° = 61°
2x = 61 - 5
2x = 56
x = 28
Hello!
Your answer would be 6
Than basically means switching the numbers
So basically if you were to multiply 6 x 6 (6 times less than)
You would get 36. Then subtract.
42 - 36 = 6, which is your answer.
I hope this helps!
Im one Brainliest away from next rank, so if possible please consider!
Answer:
12
Step-by-step explanation:
