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Ainat [17]
3 years ago
13

A pendulum is released from rest at point A. If the horizontal line represents the reference point, the pendulum has energy at p

oint B.
Physics
2 answers:
PSYCHO15rus [73]3 years ago
7 0

b i think

hope it helps ^^

Rzqust [24]3 years ago
6 0
Only kinetic

______________

Okay?


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HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLE
Romashka [77]

A_x = 5.0

A_y = -6.3

6 0
2 years ago
At Hoover Dam, the distance the water effectively falls before encountering the electric generators depends on the water levels
pashok25 [27]

Answer:

Explanation:

recall that power is energy carried out or work done per time

P=W/t

P=2*10^6*35

t=6*60=420S

W=Energy

E=2*10^6*35*360S

E=25200000000

Energy stored by water from rest is called potential energy. Since the water is falling from a height , we calculate potential energy as thus

E=M*g*h

Assume that the water intakes are effectively 175 m above the electric generators. How much water must pass through the generators to power 2 million 35-W Las Vegas light bulbs for 6.0 minutes?

M=mass of water

g=acceleration due to gravity 9.81m/s^2

h=height ,175m

25200000000=M*9.81*175

M=\frac{25200000000}{175*9.81}

M=1716.75kg

3 0
3 years ago
The current in an electric hair dryer is 10
Vikki [24]
First let's convert the time in seconds:
\Delta t= 5 min= 5 min \cdot (60 s/min)= 300 s

The current is defined as the quantity of charge flowing through a certain section of a circuit per unit of time:
I= \frac{Q}{\Delta t}
Using I=10 A, and \Delta t=300 s, we can find the amount of charge flown through the hair dryer in this time:
Q=I \Delta t=(10 A)(300 s)=3000 C

The charge of a single electron is q=1.6 \cdot 10^{-19} C, so the number of electrons flown through the hair dryer is the total charge divided by the charge of a single electron:
N= \frac{Q}{q}= \frac{3000 C}{1.6 \cdot 10^{-19} C} =1.88 \cdot 10^{22}
8 0
3 years ago
A parallel beam of light of wavelength 4.5 x 10^-7 m is incident on a pair of slits that are 5.0 x 10^-4 m apart. The interferen
RSB [31]

Answer:

1.8x10⁻³m

Explanation:

From the question above, the following information was used to solve the problem.

wavelength λ = 4.5x10⁻⁷m

Length L = 2.0 meters

distance d = 5 x 10₋⁴m

ΔY = λL/d

= 4.5x10⁻⁷m (2) / 5 x 10₋⁴m

= 0.00000045 / 0.0005

= 0.0000009/0.0005

= 0.0018

= 1.8x10⁻³m

from the solution above The separation between two adjacent bright fringes is most nearly 1.8x10⁻³m

thank you!

3 0
3 years ago
A) the unstretched length of each elastic rope is 24m. The rope obeys hookes law. The vertical distance between P and Q is 35m.
solong [7]

Explanation:

a) The rope obeys Hooke's law, so:

F = k Δx

The elastic energy in the rope is:

EE = ½ k Δx²

Or, in terms of F:

EE = ½ F Δx

Use trigonometry to find the stretched length.

cos 20° = 35 / x

x =  37.25

So the displacement is:

Δx = 37.25 − 24

Δx = 13.25

The elastic energy per rope is:

EE = ½ (3.7×10⁴ N) (13.25 m)

EE = 245,000 J

There's two ropes, so the total energy is:

2EE = 490,000 J

Rounded to one significant figure, the elastic energy is 5×10⁵ J.

b) The elastic energy in the ropes is converted to gravitational energy.

EE = PE = mgh

5×10⁵ J = (1.2×10³ kg) (9.8 m/s²) h

h = 42 m

Rounded to one significant figure, the height is 40 m.  So the claim is not justified.

6 0
3 years ago
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