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2 years ago

13

A pendulum is released from rest at point A. If the horizontal line represents the reference point, the pendulum has energy at p

oint B.

2 answers:

PSYCHO15rus [73]2 years ago

7 0

b i think

hope it helps ^^

Rzqust [24]2 years ago

6 0

Only kinetic

______________

Okay?

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An increase in temperature the kinetic energy and average speed of the gas particles. As a result, the pressure on the walls of

Cerrena [4.2K]

Answer:

a

The pressure will increase

b

$T_2 = 576^oC$

Explanation:

From the ideal gas law we have that

$PV = nRT$

We see that the temperature varies directly with the pressure so if there is an increase in temperature that pressure will increase

The initial temperature is $T_i = 10^oC = 10 + 273 = 283 \ K$

The objective of this solution is to obtain the temperature of the gas where the pressure is tripled

Now from the above equation given that nR and V are constant we have that

$\frac{P}{T} = constant$

=> $\frac{P_1}{T_1} =\frac{P_2}{T_2}$

Let assume the initial pressure is $P_1 = 1 Pa$

So tripling it will result to the pressure being $P_2 = 3 Pa$

So

$\frac{1}{283} =\frac{3}{T_2}$

=> $T_2 = 3 * 283$

=> $T_2 = 3 * 283$

=> $T_2 = 849 \ K$

Converting back to $^oC$

$T_2 = 849 - 273$

=> $T_2 = 576^oC$

8 0

2 years ago

A 4.6-kg block of ice originally at 263 K is placed in thermal contact with a 15.7-kg block of silver (cAg = 233 J/kg-K) which i

Viktor [21]

Answer:

temperature at 326.44 K system achieve equilibrium

Explanation:

given data

mass of block of ice = 4.6 kg

temperature = 263 K

thermal contact = 15.7-kg

specific heat of silver cAg = 233 J/kg-K

initially temperature = 1052 K

to find out

what temperature will the system achieve equilibrium

solution

first we consider final temperature of the system is T

we know that specific heat of water (C w) = 4186 J(kg K)

and

specific heat of ice ( C i ) = 2030 J/(kg K)

and

latent heat of fusion of ice ( Lf ) = 3.33 × $10^{5}$ J/kg

and we know that system is insulated

so heat lost by silver = heat generated by ice .................1

so we can say

mass of silver × specific heat of silver × ( initial temp - final temp ) = mass of ice × specific heat of ice × ( ice temp ) + mass of ice × latent heat of fusion of ice + mass of ice × specific heat of water × (final temperature )

put here value we get

mass of silver × specific heat of silver × ( initial temp - final temp ) = mass of ice × specific heat of ice × ( ice temp ) + mass of ice × latent heat of fusion of ice + mass of ice × specific heat of water × (final temperature )

15.7 × 233 × ( 1052 - T ) = 4.6 × 2030 × 10 + 4.6 × 3.33 × $10^{5}$ + 4.6 × 4286 × ( T - 273 )

solve we get

T = 326.44 K

so temperature at 326.44 K system achieve equilibrium

7 0

2 years ago

Acceleration problem <br> Show work plz

Dennis_Churaev [7]

Answer:

The answer to your question is: vo = 25 m/s

Explanation:

data

a = -7.5 m/s²

d = 42 m

vf = 0 m/s

vo = ?

Formula

vf² = vo² - 2ad

Substitution

0² = vo² - 2(7.5)(42)

We clear vo from the equation

vo² = 2(7.5)(42)

vo² = 630 simplifying

vo = 25 m/s result

3 0

2 years ago

12. A boy of mass 50 kg running 5m/s jumps on to a 20kg trolley

atroni [7]

Answer:

4 m/s

Explanation:

Momentum is conserved.

m₁ v₁ + m₂ v₂ = (m₁ + m₂) v

(50)(5) + (20)(1.5) = (50 + 20) v

v = 4

The final velocity is 4 m/s.

7 0

2 years ago

What energy is calculated from an object’s mass, height, and the acceleration due to gravity? A. elastic kinetic B. elastic pote

Alex777 [14]

Answer: C. gravitational kinetic

Explanation: Gravitational potential energy is the energy calculated from an object's mass height and the acceleration due to gravity. The gravitational potential energy is the energy an object has as a result of the position of the object in a gravitational field.

3 0

2 years ago

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