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3 years ago

8/7 = 12/k solve for k

Mathematics

2 answers:

Serjik [45]3 years ago

7 0

Answer:

k = 10.5

Step-by-step explanation:

8/7 = 12/k

Using cross products

8k = 7*12

8k = 84

Divide each side by 8

8k/8 = 84/8

k = 10.5

devlian [24]3 years ago

5 0

Answer:

k= 10.5

Step-by-step explanation:

We can solve this by using cross multiplication

We multiply the values across from each other

8k=7(12)

Then we multiply 7 and 12, and then divide by 8

8k=84

k= 10.5

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Eliza is a chef at a restaurant. she is making spaghetti sauce and put 14 tomatoes and 4 onions in the pot. what is the ratio of

notka56 [123]

Here,
tomato = 14
onion = 4
then,
ratio of tomato to onion = 14/4
= 7/2

7 0

3 years ago

At her restaurant .Yolanda open 285 cans of tomato sauce .She need to use 4 can of for one pan of lasagna how many pans of lasag

Rudiy27

Answer:

71 1/4 pans of lasagna

Step-by-step explanation:

4 cans of tomato sauce = 1 pan of lasagna

285 cans of tomato sauce = x pan of lasagna

4 = 1

285 = x

Cross product

4*x = 285*1

4x = 285

x = 285/4

x = 71 1/4 pans of lasagna

8 0

2 years ago

I have an idea on how to do this I just need to make sure it’s right or not but I’ll mark you!

Akimi4 [234]

Answer:

I think it's 300

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the range of the function y=2x+1 for the domain 2<=x<=5?

egoroff_w [7]

So domain is the number you can use
range is the output your get from inputting the domain given
so from 2≤x≤5
since it is linear, we can be sure that we only need to test the endpoints of the domain to find the endpoints of the range

sub 2 for x
y=2(2)+1
y=4+1
y=5

sub 5 for x
y=2(5)+1
y=10+1
y=11

so range is from 5 to 11
in interval notation: [5,11]
in other notation 5≤y≤11
or
R={y|5≤y≤11}

5 0

3 years ago

Solve the system of equations. x+y=4 y=x^2 - 8x + 16 a) {(-3,7).(-4, 8)} b) [(4,0)} c) {(3,1),(4,0) d) {(3,7). (4.0)} e) none

Marysya12 [62]

Answer: The required solution of the given system is

(x, y) = (3, 1) and (4, 0).

Step-by-step explanation: We are given to solve the following system of equations :

$x+y=4~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x^2-8x+16~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

From equation (i), we have

$x+y=4\\\\\Rightarrow y=4-x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of y from equation (iii) in equation (ii), we get

$y=x^2-8x+16\\\\\Rightarrow 4-x=x^2-8x+16\\\\\Rightarrow x^2-8x+16-4+x=0\\\\\Rightarrow x^2-7x+12=0\\\\\Rightarrow x^2-4x-3x+12=0\\\\\Rightarrow x(x-4)-3(x-4)=0\\\\\Rightarrow (x-3)(x-4)=0\\\\\Rightarrow x-3=0,~~~~~~~x-4=0\\\\\Rightarrow x=3,~4.$

When, x = 3, then from (iii), we get

$y=4-3=1.$

And, when x = 4, then from (iii), we get

$y=4-4=0.$

Thus, the required solution of the given system is

(x, y) = (3, 1) and (4, 0).

8 0

3 years ago