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Nina [5.8K]
3 years ago
11

I really need help with this problem, i don't understand it.7p−(−5)+(−1)

Mathematics
2 answers:
DedPeter [7]3 years ago
4 0
7p+5-1 which is 7p+4
MariettaO [177]3 years ago
3 0

just simplify the expression to 7p+4

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Someone please help me!!!
Paha777 [63]

Answer:

8

Step-by-step explanation:

\cos(51)  =  \frac{5.3}{x}

X = 5.3/0.6293

X = 8.4

4 0
3 years ago
Every week Kabore gets paid $100 plus 5% of his sales. How much does he need to sell if he wants to make $700 this week?
sveta [45]

Answer:

$12,000

Step-by-step explanation:

Kabore wants to make $700 this week. We can subtract 100 from that amount because his base pay is $100.

700 - 100 = 600

This leaves us with 600. Kabore has to make $600 from his sales. However, he only gets paid 5% of his sales. So, 600 is worth 5% of his sales. This can be represented in an equation, where x represents his sales and 0.05 is 5% in decimal form:

\frac{600}{x} = 0.05

Multiply both sides of the equation by x to isolate it on one side:

600 = 0.05x

Divide both sides by 0.05 to find the value of x:

12000 = x

Kabore needs to sell $12,000 worth of product if he wants to make $700 this week.

Hope this helps :)

5 0
3 years ago
When two lines intersect to form a 90 degree angle, these lines are called ________ lines?
zalisa [80]
When two lines intersect to form a 90 degree angle, these lines are called perpendicular lines.
5 0
4 years ago
Read 2 more answers
Please help me with these I'm lost
Inessa [10]
Y = (2/3)x + 6
3y - 5x = 9

find an expression for y from the second equation:-
y = (5/3)x + 3
Now substitute this for y in the first equation:-
(5/3) x + 3 = (2/3)x + 6  Now solve for x:-
(5/3)x - (2/3)x  = 6 - 3
x = 3
Now plug x = 3 into the second equation to find the value of y:_
3y - 5(3) =9
3y = 15+9 = 24
y = 8
So the solution is x = 3, y = 8

written as a set this is {3,8}.
3 0
3 years ago
A freight train takes 18 hours to travel the same distance that an express train travels in 15 hours. The rate of the express tr
Eva8 [605]
<span>The rate of the express train is 15 mph faster than the freight train.
Let's grasp onto this piece of information. 

The rate at which the freight train goes will be labeled "x" (keep in mind rate is just the speed)

If the freight train has a speed of "x" then the express train which is going 15mph faster than the freight train can be represented as "x + 15mph."

Our result is in HOURS, but our speed is in Miles per Hour (Miles/Hour). Meaning we need to multiply our speeds by some time (t).

Let's set up two equations: 
Freight Train: 18 hours * x mph = distance
Express Train: 15 hours * (x mph + 15mph) = distance

They are both the same distance so we can set the two equations equal to each other like this: 

18 hours * x mph = 15 hours * (x mph + 15mph)

That right side is a bit of a thorn in our side, so let's simplify it by multiplying all the terms in the parenthesis by 15 hours (keep in mind the hours in the units cancel out). 

18 hours * x mph = 15x miles + 15 * 15 miles
18 hours * x mph = 15x miles + 225 miles

Let's simplify the left side (</span>\frac{miles}{hour}*hour = miles)

18x miles = 15x miles + 225 miles

Get all the "x" terms on one side by subtracting 15x on both sides. 

18x - 15x = 225 miles

Simplify

3x = 225 miles

Divide by 3 on both sides to solve for x. 
225/3 

225 = 25*9

(25*9)/3 = 25*3 = 75mph

So "x" which we chose was the rate of the freight train is 75mph. 
Adding 15mph to the freight train rate gives you the express trains rate which is 90mph. 

Hope that helped. 
8 0
3 years ago
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