Hardness is an example of

Chemistry

1 answer:

wolverine [178]3 years ago

5 0

Hardness is an example of volume

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2AlF3 + 3K2O → 6KF + Al2O3

Agata [3.3K]

<h3>Answer:</h3>

7.4797 g AlF₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN] 2AlF₃ + 3K₂O → 6KF + Al₂O₃

[Given] 15.524 g KF

<u>Step 2: Identify Conversions</u>

[RxN] 6 mol KF = 2 mol AlF₃

Molar Mass of K - 39.10 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of Al - 26.98 g/mol

Molar Mass of KF - 39.10 + 19.00 = 58.1 g/mol

Molar Mass of AlF₃ - 26.98 + 3(19.00) = 83.98 g/mol

<u>Step 3: Stoichiometry</u>

Set up: $\displaystyle 15.524 \ g \ KF(\frac{1 \ mol \ KF}{58.1 \ g \ KF})(\frac{2 \ mol \ AlF_3}{6 \ mol \ KF})(\frac{83.98 \ g \ AlF_3}{1 \ mol \ AlF_3})$
Multiply/Divide: $\displaystyle 7.47966 \ g \ AlF_3$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 5 sig figs.</em>

7.47966 g AlF₃ ≈ 7.4797 g AlF₃

3 0

3 years ago

The isotope tritium has a half-life of 12. 3 y. Assume we have 11 kg of the substance. How much tritium will be left after 51 y?

Mama L [17]

Half-life is a time in which the concentration of the substance gets reduced to 50% of the initial concentration. The number of tritium that will be left after 51 years is 0.624 kg.

<h3>What is an isotope?</h3>

Isotopes are chemical substances that have the same atomic number but different atomic mass because they have a different number of neutrons in the nuclei.

The half-life of the isotope, tritium is 12.3 years. Assuming we have 11 kg of substance and a number of years 51 years.

$11 \times 2 ^{\frac{-51}{12.3}} = 0.6239 \;\rm kg$