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Brums [2.3K]
3 years ago
10

A rigid vessel filled to 0.8 of its volume with liquid nitrogen at its normal boiling point is allowed to warm to 25°C. What pre

ssure is developed? The molar volume of liquid nitrogen at its normal boiling point is 34.7 cm3·mol–1.
Chemistry
1 answer:
rodikova [14]3 years ago
5 0

Answer:

704.25 atm

Explanation:

From the ideal gas equation

PV = nRT

P = nRT/V

Molar volume (V/n) = 34.7 cm^3/mol, n/V = 1/34.7 = 0.0288 mol/cm^3

R = 82.057 cm^3.atm/mol.K

T = 25°C = 25+273 = 298 K

P = 0.0288 × 82.057 × 298 = 704.25 atm

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Answer: electrons

Explanation:

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3 years ago
Which class of organic compounds has molecules that contain nitrogen atoms?
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2) amine is the correct answer 
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Place the following substances in order of increasing vapor pressure at a given temperature.
Butoxors [25]

Answer:

NH3 < NF3 < BCl3

Explanation:

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4 years ago
A chemist must prepare of aqueous potassium permanganate working solution. He'll do this by pouring out some aqueous potassium p
sineoko [7]

Answer:

V₁ = 228 mL

Explanation:

There is some info missing. I think this is the original question.

<em>A chemist must prepare 575 mL of 50.0 mM aqueous potassium permanganate (KMnO₄) working solution. He'll do this by pouring out some 0.126M aqueous potassium permanganate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the potassium permanganate stock solution that the chemist should pour out. Round your answer to 3 significant digits.</em>

<em />

We want to prepare 575 mL (V₂) of a 50.0 mM solution (C₂). To do so, we start, from a stock solution of concentration C₁ = 0.126 M. In order to find the volume V₁ that the chemist should pour out, we will use the dilution rule.

C₁ × V₁ = C₂ × V₂

0.126 M × V₁ = 50.0 mM × 575 mL

0.126 M × V₁ = 50.0 × 10⁻³ M × 575 mL

V₁ = 228 mL

4 0
3 years ago
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ArbitrLikvidat [17]

Answer:

7:4

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4 0
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