Which type of radioactive decay produces particles with the most mass? Alpha.
193.38 K was the initial temperature of the krypton.
Explanation:
Data given:
Initial volume of the krypton gas = 6 litres
initial pressure of the krypton gas = 0.960 atm
initial temperature of the krypton gas = ?
final volume of the krypton gas = 7.70 litres
final pressure of the Krypton gas = 1.25 atm
final temperature of the krypton gas = 55 degrees or 273.25+55 = 323.15 K
Applying the Combined Gas Laws:

Rearranging the equation:
T1 = 
Putting the value in the equation:
T1 = 
T1 = 193.38 K
Initial temperature of the krypton gas is 193.78 K
The 2.5 x 10²¹ molecules of CH₃OH have 0.00415 moles.
<h3>What is the mole concept?</h3>
- The Mole concept is used to express the amount of substance conveniently.
- A mole is defined as the amount of substance that contains exactly 6.022 x 10²³ elementary particles of the given substance. Here, elementary particles refer to atoms, molecules, or ions.
- This fixed number 6.022 x 10²³ is known as Avogadro Number and is denoted by

<h3>How to calculate the number of moles?</h3>
The number of moles is given by

When given mass = molar mass of a substance, then no of moles is equal to 1 which is equivalent to 6.022 x 10²³.
We also know,
1 mole has 6.022 x 10²³ molecules of CH₃OH
According to the mole concept,
6.022 x 10²³ molecules of CH₃OH is equal to 1 mole
2.5 x 10²¹molecules of CH₃OH is equal to
moles
Thus, 2.5 x 10²¹molecules of CH₃OH are equal to 4.15 x 10⁻³ moles or 0.00415 moles
Learn more about the mole concept:
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Answer:
45.2g produce x mole of CH4. we are given the mass of methane. mass (CH4)=45.2g. molar mass (CH4) = 12+4 =16g/mol. Mole=mass. molar mass. mole=45.2. 16. mole=2.8mol. therefore, if 45.2g produce 2.8mol as 1 mole of methane, the water produced is 2(2.8) we Are multiplying by 2 because the water is having 2 moles water mole is 5.6mol
Explanation:
45.2g produce x mole of CH4. we are given the mass of methane. mass (CH4)=45.2g. molar mass (CH4) = 12+4 =16g/mol. Mole=mass. molar mass. mole=45.2. 16. mole=2.8mol. therefore, if 45.2g produce 2.8mol as 1 mole of methane, the water produced is 2(2.8) we Are multiplying by 2 because the water is having 2 moles water mole is 5.6mol
Your answer would be 15 kg*m/sec