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Brums [2.3K]
3 years ago
10

A rigid vessel filled to 0.8 of its volume with liquid nitrogen at its normal boiling point is allowed to warm to 25°C. What pre

ssure is developed? The molar volume of liquid nitrogen at its normal boiling point is 34.7 cm3·mol–1.
Chemistry
1 answer:
rodikova [14]3 years ago
5 0

Answer:

704.25 atm

Explanation:

From the ideal gas equation

PV = nRT

P = nRT/V

Molar volume (V/n) = 34.7 cm^3/mol, n/V = 1/34.7 = 0.0288 mol/cm^3

R = 82.057 cm^3.atm/mol.K

T = 25°C = 25+273 = 298 K

P = 0.0288 × 82.057 × 298 = 704.25 atm

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How would I fill out this chart?
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[Top row] - Chemical bonds

[2nd Row L-R] - Force, Ionic, Covalent

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I have been able to fill the concept map using the correct terms or phrases. The concept map talks about chemical bonds. There are two types of chemical bonds; which ionic bond and covalent bond.  

3 0
3 years ago
How many molecules are in 145.5 grams of Be(OH)2
Zanzabum

Answer:

2.04 x 10²⁴ molecules

Explanation:

Given parameters:

Mass of Be(OH)₂ = 145.5g

To calculate the number of molecules in this mass of Be(OH)₂ we follow the following steps:

>> Calculate the number of moles first using the formula below:

Number of moles = mass/molarmass

Since we have been given the mass, let us derive the molar mass of Be(OH)₂

Atomic mass of Be = 9g

O = 16g

H = 1g

Molar Mass = 9 + 2(16 + 1)

= 9 + 34

= 43g/mol

Number of moles = 145.5/43 = 3.38mol

>>> We know that a mole is the amount of substance that contains Avogadro’s number of particles. The particles can be atoms, molecules, particles etc. Therefore we use the expression below to determine the number of molecules in 3.38mol of Be(OH)₂:

Number of

molecules= number of moles x 6.02 x 10²³

Number of molecules= 3.38 x 6.02 x 10²³

= 20.37 x 10²³ molecules

= 2.04 x 10²⁴ molecules

3 0
2 years ago
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