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Brums [2.3K]
3 years ago
10

A rigid vessel filled to 0.8 of its volume with liquid nitrogen at its normal boiling point is allowed to warm to 25°C. What pre

ssure is developed? The molar volume of liquid nitrogen at its normal boiling point is 34.7 cm3·mol–1.
Chemistry
1 answer:
rodikova [14]3 years ago
5 0

Answer:

704.25 atm

Explanation:

From the ideal gas equation

PV = nRT

P = nRT/V

Molar volume (V/n) = 34.7 cm^3/mol, n/V = 1/34.7 = 0.0288 mol/cm^3

R = 82.057 cm^3.atm/mol.K

T = 25°C = 25+273 = 298 K

P = 0.0288 × 82.057 × 298 = 704.25 atm

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IRINA_888 [86]

<em>The mass of a gold bar  = 1.424 x 10⁴ gram</em>

<em></em>

<h3><em>Further Explanation</em></h3>

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than type

The unit of density can be expressed in g / cm3 or kg / m3

Density formula:

\large{\boxed{{\bold{\rho~=~\frac{m}{V}}}}

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm3

The mass itself is often equated with weight, even though it is different. Mass is the amount of matter in the matter while weight is related to the gravitational force

<em>Known variable</em>

volume gold bar 7.379 × 10⁻⁴ m³

a density of 19.3 g/cm³

<em>Asked</em>

the mass of a gold bar

<em>Answer</em>

volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density

7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³

then:

mass = volume x density

mass = 7.379 × 10² cm³ x 19.3 g/cm³

mass = 1.424 x 10⁴ gram

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Keywords: density, mass, volume, a gold bar

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