178.87 grams of sulphur dioxide is formed according to the equation given.
Explanation:
The balanced chemical reaction for the process is:
4 FeS2 + 11 O2 ⇒ 2Fe2O3(-) + 8 SO2
the reaction involving FeS and oxygen having balanced chemical equation as:
moles of oxygen given as 3.84
so when 11 moles of O2 reacts to form 8 moles SO2
3.84 moles of oxygen reacts to form x moles of SO2
= 
x = 
2.792 moles of sulphur dioxide will be formed
The mass can be calculated as number of moles x molar mass of 1 mole of SO2
= 2.792 x 64.066
= 178.87 grams of sulphur dioxide is formed.
There are two oxygen atoms in an oxygen molecule. Denoted by the 2 following O
60 days have passed. In every 12 days the radioisotope loses half of its life. So in the first 12 days, from 160 grams it decreases to half so it becomes 80 grams. The second 12 days, from 80 grams, it decreases to half and becomes 40 g. The third 12 days, from 40 it becomes half to 20 g. The fourth 12 days, from 20 g it becomes half to 10 g. And in the fifth 12 days, from 10 g it becomes half to 5 grams. So 5 times it became half.
5 x 12 ( days)= 60 days
We need draw the structure of (3E,5E)-2,5-dibromo-3,5-octadiene.
The structure is shown below:
The molecule has two double bonds in 3 and 5 position and two Br-atoms attached to 2 and 5 position.
The configuration is 3E and 5E. E configuration indicates cis- isomers where similar groups are in same side with respect to double bonds.
Answer:
Explanation:
The temperature and amount of gas are constant, so we can use Boyle’s Law.
Data:
Calculations:
