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3 years ago

How does a generator transform mechanical energy into electrical energy?

Chemistry

1 answer:

RSB [31]3 years ago

5 0

Answer:

C.) A generator transforms mechanical energy into electrical energy with the help of static electricuty

Example:

they convert mechanical or chemical energy into electrical energy. They do this by capturing the power of motion and turning it into electrical energy by forcing electrons from the external source through an electrical circuit.

(Hope this helps) sorry if it's wrong

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How much volume would 0.450 mol CO2 gas occupy?

umka21 [38]

Answer:

10.08 L.

Explanation:

If we assume that CO₂ gas behaves ideally at STP (standard T(0.0 °C) and P(1.0 atm)):

It is known that 1.0 mole of ideal gas occupies 22.4 L at STP conditions.

Using cross multiplication:

1.0 mole of CO₂ gas occupies → 22.4 L.

0.45 mole of CO₂ gas occupies → ??? L.

∴ The volume occupied by 0.45 mole of CO₂ gas = (0.45 mol)(22.4 L)/(1.0 mol) = 10.08 L.

5 0

3 years ago

What ingredients are needed to turn the cake mix into cake batter

svp [43]

Answer:

Ingredients

2 ⅓ cups all-purpose flour.

1 tablespoon baking powder.

¾ teaspoon salt.

1 ½ cups white sugar.

½ cup shortening.

2 eggs.

1 cup milk.

1 teaspoon vanilla extract.

Explanation:

4 0

3 years ago

Why do thermistors increase in conductivity when heated? What happens in normal metals? Explain on the atomic level.

Marysya12 [62]

Metal conductivity generally goes down or resistivity goes up with temperature goes up.

7 0

2 years ago

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi

AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

$3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)$

Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

4 0

3 years ago

Balance the following redox reaction occurring in an acidic solution. The coefficient of Mn2+(aq) is given. Enter the coefficien

Vadim26 [7]

Answer:

_5_ AsO2−(aq) + 3 Mn2+(aq) + _2_ H2O(l) → _5_ As(s) + _3_ MnO4−(aq) + _4_ H+(aq)

Explanation:

Step 1:

The unbalanced equation:

AsO2−(aq) + 3 Mn2+(aq) + H2O(l) → As(s) + MnO4−(aq) + H+(aq)

Step 2:

Balancing the equation.

AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + MnO4−(aq) + H+(aq)

The above equation can be balanced as follow:

There are 3 atoms of Mn on the left side of the equation and 1 atom on the right side. It can be balance by putting 3 in front of MnO4− as shown below:

AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + 3MnO4−(aq) + H+(aq)

There are 12 atoms of O on the right side and a total of 3 atoms on the left side. It can be balance by putting 5 in front of AsO2− and 2 in front of H2O as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → As(s) + 3MnO4−(aq) + H+(aq)

There are 4 atoms of H on the left side and 1 atom on the right side. It can be balance by putting 4 in front of H+ as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → As(s) + 3MnO4−(aq) + 4H+(aq)

There are 5 atoms of As on the left side and 1 atom on the right side. It can be balance by putting 5 in front of As as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → 5As(s) + 3MnO4−(aq) + 4H+(aq)

Now the equation is balanced

7 0

3 years ago