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2 years ago

How many different kinds of atoms are present in the mixture

1 answer:

7 0

Mixture is made up two or more different elements which are physically combined but not chemically combined called a mixture.

<h3>How many different kinds of atoms are present in the mixture?</h3>

The Mixture is made up of two or more different elements and/or compounds physically combined with each other,and can be separated into its components by physical means, and. often retains many of the properties of its components. There are 118 different elements. They are listed on the periodic table . Examples of elements include oxygen, hydrogen and carbon.

So we can conclude that: Mixture is made up two or more different elements which are physically combined but not chemically combined called a mixture.

Learn more about Mixture here: brainly.com/question/1917079

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3 years ago

Read 2 more answers

What is the conecntration of Fe3 and the concentration of No3- present in the solution that result when 30.0 ml of 1.75M Fe(No3)

zvonat [6]

Answer:

$[Fe^{+3}]=0.700 M$

$[NO_{3}^{-}]=2.10 M$

Explanation:

Here, a solution of Fe(NO₃)₃ is diluted, as the total volume of the solution has increased. The formula for dilution of the compound is mathematically expressed as:

$C_{1}. V_{1}= C_{2}.V_{2}$

Here, C and V are the concentration and volume respectively. The numbers at the subscript denote the initial and final values. The concentration of Fe(NO₃)₃ is 1.75 M. As ferric nitrate dissociates completely in water, the initial concentration of ferric is also 1.75 M.

Solving for [Fe],

$[Fe^{+3}]=\frac{C_{1}.V_{1}}{V_{2} }$

$[Fe^{+3}]=\frac{(1.75).(30.0)}{45.0+30.0 }$

$[Fe^{+3}]=0.700 M$

For [NO₃⁻],

There are three moles of nitrate is 1 mole of Fe(NO₃)₃. This means that the initial concentration of nitrate ions will be three times the concentration of ferric nitrate i.e., it will be 5.25 M.

$[NO_{3}^{-}]=\frac{C_{1}.V_{1}}{V_{2} }$

$[NO_{3}^{-}]=\frac{(5.25)(30.0)}{30.0+45.0 }$

$[NO_{3}^{-}]=2.10 M$

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3 years ago