In the reaction of sulfur with oxygen, which atom is reduced?
1 answer:
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Oxid # : 0 0 +2 -1
∴ the nickel was oxidized while chlorine was reduced
nickel reduction potential = - 0.25 V
but since it is being oxidised the you have to switch the integer sign so the
the potential of nickel in this case becomes + 0.25 V
chlorine was reduced thus its reduction potential remains same = + 1.36 V
Overall Cell potential = ∑ of half cell potential
The overall cell potential = (+ 1.36) + (+ 0.25)
= + 1.61 V
∴ the answer would be D
∴ the nickel was oxidized while chlorine was reduced
nickel reduction potential = - 0.25 V
but since it is being oxidised the you have to switch the integer sign so the
the potential of nickel in this case becomes + 0.25 V
chlorine was reduced thus its reduction potential remains same = + 1.36 V
Overall Cell potential = ∑ of half cell potential
The overall cell potential = (+ 1.36) + (+ 0.25)
= + 1.61 V
∴ the answer would be D