Expected number of wins=number of plays times the probability of winning
w=20(14.5/100)
w=20(0.145)
w=2.9
w≈3
So you would expect to win 3 times out of 20 attempts (rounded to the nearest whole number of wins)
The correct answer should be A
Add all of the numbers by using an odd number.
1+1= 2
2+3= 5
5+5=10
10+7= 17
17+9= 26
26+11= 37
Answer:1 , 2, 5, 10, 17, 26, 37
Answer:
So in range "-35.6108 to 39.73"; 50% data set can be found
ux = 37.6704 unites
Step-by-step explanation:
Step One: State the given parameters
From the question we are given that
mean Ц =2.06 unites
Standard deviation б is = 55.85 unites
Probability density → Normal
Let assume that it is symmetrically distributed about the mean
Step Two: Determine the range of the values
Our goal is to determine the range of values in which 50% of the data set should be found . Assuming that the range is from
to
and between these these we found 50% data set Hence from 0 up to
we found 25% and up to
we found 75% of the data set therefore z value corresponding to
is - 0.6745 and the the z value corresponding to
is +0.6745 (Refer to the z-table for normal distribution) as shown o the diagram on the first uploaded image
The formula for z is
z = 
for
,z = - 0.6745 ,substituting into the formula

=> -37.67 =
-2.06
=>
= -35.6108 unites
for
, z = 0.6745 , substituting into the formula

=> 37.67 =
-2.06
=>
= 39.73 units
So in range "-35.6108 to 39.73"; 50% data set can be found
ux = (39.73 - (-35.73) )/2
= 37.6704 unites
X=67.5 or 135/2 or 67 1/2