Okay, I will start talking you through it, it'll be quick but I need your response. Just leave a comment! Loves,
-Brainiac224
Answer:
a) 29.23% probability that a randomly selected home run was hit to right field
b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.
(a) What is the probability that a randomly selected home run was hit to right field?
Desired outcomes:
19 home runs hit to right field
Total outcomes:
65 home runs
19/65 = 0.2923
29.23% probability that a randomly selected home run was hit to right field
(b) Was it unusual for this player to hit a home run to right field?
29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
prob( it lands on open end) = 8/20 = 2/5
prob ( lands on closed end) = 4/20 = 1/5
The second choice is correct.
<span>A random sample is drawn from a population with mean μ = 66 and standard deviation σ = 5.5. use table 1.
a. is the sampling distribution of the sample mean with n = 16 and n = 36 normally distributed? yes, both the sample means will have a normal distribution. no, both the sample means will not have a normal distribution. no, only the sample mean with n = 16 will have a normal distribution. no, only the sample mean with n = 36 will have a normal distribution.
b. can you use the standard normal distribution to calculate the probability that the sample mean falls between 66 and 68 for both sample sizes? yes, for both the sample sizes, standard normal distribution could be used. no, for both the sample sizes, standard normal distribution could not be used. no, only for the sample size with n = 16, standard normal distribution could be used. no, only for the sample size with n = 36, standard normal distribution could be used.
c. calculate the probability that the sample mean falls between 66 and 68 for n = 36. (round intermediate calculations to 4 decimal places, "z" value to 2 decimal places, and final answer to 4 decimal places.)</span>
She played 18 games, so subtract 18 from 40 to get your answer
She did NOT play 22 games
Hope I helped!
