Answer:
1.55 h
Explanation:
Let the time to spend over dinner be t.
Since I need to spend 10.8 h for the whole trip, then I have 10.8 - t hours left to drive.
Speed = distance/time
![v = \dfrac{d}{10.8-t}](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7Bd%7D%7B10.8-t%7D)
![d = v(10.8-t)](https://tex.z-dn.net/?f=d%20%3D%20v%2810.8-t%29)
The distance is 549 and maximum speed is 65 mi/h.
![549 = 65(10.8 - t)](https://tex.z-dn.net/?f=549%20%3D%2065%2810.8%20-%20t%29)
![10.8-t = 8.45](https://tex.z-dn.net/?f=10.8-t%20%3D%208.45)
![t = 10.8 - 8.45 = 1.55 \text{ h}](https://tex.z-dn.net/?f=t%20%3D%2010.8%20-%208.45%20%3D%201.55%20%5Ctext%7B%20h%7D)
Initial conditions
K is the spring constant
X is the compression of the spring
Answer:
X
Explanation:
v=u+at but t is constant so
a=v-u
for x
a=29-10
a=19
which marks the greater acceleration
The work done is 46 J
Explanation:
The work done by a force pushing a body is given by
![W=Fd cos \theta](https://tex.z-dn.net/?f=W%3DFd%20cos%20%5Ctheta)
where
F is the magnitude of the force
d is the displacement of the body
is the angle between the directions of the force and of the body
In this problem:
F = 23 N
d = 2 m
(we assume the force is parallel to the displacement)
Therefore, the work done is
![W=(23)(2)=46 J](https://tex.z-dn.net/?f=W%3D%2823%29%282%29%3D46%20J)
Learn more about work:
brainly.com/question/6763771
brainly.com/question/6443626
#LearnwithBrainly
Answer: a = 1.32m/s2
Therefore, the average acceleration is 1.32m/s2
Explanation:
Acceleration is the rate of change in the velocity per time
a = change in velocity/time
a = ∆v/t
average acceleration a = (v2 -v1)/t. ....1
Given;
Final velocity v2 = 1.63m/s
Initial velocity v1 = -1.15ms
time taken t = 2.11s
Substituting into eqn 1
a = [1.63 - (-1.15)]/2.11
a = (1.63+1.15)/2.11
a = 2.78/2.11
a = 1.32m/s2
Therefore, the average acceleration is 1.32m/s2