Question

In 2013, the world record depth for free diving without assistance was 101 m. What is the pressure in the water (assumed freshwater) at this depth?

Answer 1

Answer:

The pressure in the water is $1.1\times10^{6}\ Pa$

Explanation:

Given that,

Depth = 101 m

Let P be the pressure at the bottom of water at a depth

We need to calculate the pressure in water

Using formula of pressure

$P=P_{w}+P_{atm}$

Where, $P_{atm}$ = atmospheric pressure

$P_{w}$ = pressure in water

Put the value of $P_{w}$ in to the formula

$P=\rho hg+P_{atm}$

Put the value into the formula

$P=1000\times101\times9.8+101325$

$P=1.1\times10^{6}\ Pa$

Hence, The pressure in the water is $1.1\times10^{6}\ Pa$

Answer 2

Answer:

1092135 Pa

Explanation:

Let P be the pressure at the bottom of the water At a depth h

the pressure at the depth h = P+P_atm

P_atm= atmospheric pressure = 101325 Pa

P_{water}= ρgh

ρ= density of water = 1000 Kg/m^3

g= acc. due to gravity =9.81 m/sec^2

h=101 m

then P_{water}= 1000×9.81×101 =990810 Pa

therefore pressure at depth of 101 m of water column= 990810 Pa+101325 Pa= 1092135 Pa