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3 years ago

The isotope of an atom containing 40 protons and 51 neutrons suddenly has 2 neutrons added to it. What isotope is created?

1 answer:

7 0

The isotope of an atom containing 40 protons and 51 neutrons suddenly has 2 neutrons added to it
That is X-93 so it will be
Zirconium-93
hope it helps

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How much of the universe do scientists speculate is composed of dark energy

algol [13]

Answer: Approximately 65% from what i have learnt.

5 0

3 years ago

What type of energy I’d converted into machanical energy when a person walks

Ainat [17]

Which type of energy is converted into mechanical energy when a person walks?

A. Electromagnetic

B. Electrical

C. Nuclear

D. Chemical

That is Chemical, This is because the energy comes from the food we eat and our fat stores and thus it comes from a chemical form.

5 0

4 years ago

A constant amount of charge passes through a conductor. How is current affected if the same amount of charge passes in less time

baherus [9]

Answer:

B. The current increases.

Explanation:

As we know that rate of flow of charge through the conductor is known as electric current

So we have

$i = \frac{q}{t}$

here we know that charge Q flowing through the conductor is constant while the time in which it passes through it is decreased

so we can say that the ratio of charge and time will increase

so here we have

$i = increased$

So correct answer will be

B. The current increases.

4 0

4 years ago

what is the wavelength of radio waves transmitted by an FM station at 90MHz where 1M=10^6, and speed of radiowave is 3*10^8m/s

Igoryamba

Answer:

λ = 3.33 m

Explanation:

Given:

Frequency = f = 9 × 10⁷ Hz

Speed = v = 3 × 10⁸ m/s

Required:

Wavelength = λ = ?

Formula:

v = fλ

Solution:

Putting the givens in the formula

v = fλ

λ = $\frac{v}{f}$

λ = $\frac{3*10^8}{9*10^7}$

λ = 0.33 × 10¹

λ = 3.33 m

5 0

3 years ago

If the range of a projectile's trajectory is six times larger than the height of the trajectory, then what was the angle of laun

zvonat [6]

Answer:

H = 1/2 g t^2 where t is time to fall a height H

H = 1/8 g T^2 where T is total time in air (2 t = T)

R = V T cos θ horizontal range

3/4 g T^2 = V T cos θ 6 H = R given in problem

cos θ = 3 g T / (4 V) (I)

Now t = V sin θ / g time for projectile to fall from max height

T = 2 V sin θ / g

T / V = 2 sin θ / g

cos θ = 3 g / 4 (T / V) from (I)

cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ

tan θ = 2/3

θ = 33.7 deg

As a check- let V = 100 m/s

Vx = 100 cos 33.7 = 83,2

Vy = 100 sin 33,7 = 55.5

T = 2 * 55.5 / 9.8 = 11.3 sec

H = 1/2 * 9.8 * (11.3 / 2)^2 = 156

R = 83.2 * 11.3 = 932

R / H = 932 / 156 = 5.97 6 within rounding

3 0

3 years ago