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3 years ago

2. An object is dropped from rest. Calculate its velocity after 2.5s if it is dropped:

Physics

1 answer:

Alekssandra [29.7K]3 years ago

7 0

Answer:

a=24.5 b=9.5

Explanation:

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the oldest meteorites

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3 years ago

A 2.0 kg wooden block is slid along a concrete surface (μk = 0.21) with an initial speed of 15 m/s. How far will the block slide

exis [7]

Answer:

The distance is 54.6 m

Explanation:

Given that,

Mass = 2.0 kg

Frictional coefficient = 0.21

Initial velocity = 15 m/s

We need to calculate the acceleration

Using formula of frictional force

$F = \mu mg$

$F=0.21\times2.0\times9.8$

$F = 4.12\ N$

We need to calculate the acceleration

$F = ma$

$a = \dfrac{F}{m}$

$a =\dfrac{4.12}{2.0}$

$a=2.06\ m/s^2$

We need to calculate the initial velocity

Using equation of motion

$v^2=u^2-2as$

Put the value

$0=15^2-2\times2.06\times s$

$s = \dfrac{15^2}{2\times2.06}$

$s=54.6\ m$

Hence, The distance will be 54.6 m.

3 0

3 years ago

Economics is the study of producing and ____ goods and services.

user100 [1]

Economics is the study of producing and consuming goods and services.

Economics show the GDP, or Growth domestic product, which show if a country is making more and intaking less products compared too others. The higher the GDP, usually (unless consumption is great too), the more built up the country is.

hope this helps

3 0

4 years ago

Read 2 more answers

(a) What is the current involved when a truck battery sets in motion 720 C of charge in 4.00 s while starting an engine? (b) How

OLEGan [10]

Answer:

(a) Current flowing through truck battery is 180 A

(b) Time taken in calculator is 333.33 s

Explanation:

(a) Given:

The charge on the truck battery,q = 720 C

Time, t = 4.00 s

Consider I be the current flowing through truck battery.

The relation between current, charge and time is:

I = q/t

Substitute the suitable values in the above equation.

$I=\frac{720}{4}$

I = 180 A

(b) Given:

The charge on the calculator,q = 7.00 C

The current flowing through calculator, I = 0.3 mA = 0.3 x 10⁻³ A

Consider t be the time.

The relation between current, charge and time is:

t = q/I

Substitute the suitable values in the above equation.

$t=\frac{1}{0.3\times10^{-3} }$

I = 333.33 s

8 0

4 years ago

Consider horizontal parallel plates with a fixed potential difference. The upper plate has a voltage difference of 30 V with the

BlackZzzverrR [31]

relation between potential difference and electric field is given as

$E . d = \Delta V$

so here we know that

d = 3 cm

$\Delta V = 30 V$

$E \times 0.03 = 30$

$E = 1000 N/C$

So now when plates are separated to 4 cm distance carefully

the potential difference between them will change but the electric field between them will remain constant

So at distance of 4 cm also the electric field will be E = 1000 N/C

5 0

3 years ago