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Sunny_sXe [5.5K]
3 years ago
12

What is the prime factorization of 110? Please explain how you arrived to the answer.

Mathematics
1 answer:
Aleks [24]3 years ago
3 0

110 is a composite number, so, begin by makin a factor tree. Place 110 at the top, draw two arrows in a downward direction with 2 and 55 at the end of each. Since 2 is a prime number, move on to 55, which is also composite. Make two more downward arrows and place 5 and 11 at the ends. So, your prime factorization is 110=2*5*11.


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If a number is tripled , it give same result as 28 is added to it find the number
DiKsa [7]

Given :

If a number is tripled , it give same result as 28 is added to.

To Find :

We need to find that number.

Solution :

Let, the number is x.

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3x = x + 28

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Since at t=0, n(t)=n0, and at t=[infinity], n(t)=0, there must be some time between zero and infinity at which exactly half of t
Ostrovityanka [42]

An expression for this timet-half will be given as ln(2) / λ ≈ 0.693 / λ

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

1) Equation given:

← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N9t) = Ne^{-\lambda t}

3) Solving for α (remember α is λ)

N_{t-half}=\dfrac{N_o}{2}=N_oe^{-\alpha t}

\dfrac{1}{2} = e^{-\alpha t}2=e^{-alpha t}\alpha t=In(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ

Therefore expression for this timet-half will be given as ln(2) / λ ≈ 0.693 / λ

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I hope this helps, have a good day.

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