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qaws [65]
3 years ago
12

The price of a movie ticket in a given year can be modeled by the regression equation y = 6.94(1.02x), where y is the ticket pri

ce and x is the year. To the nearest cent, which is the best prediction of the price of a ticket in year 25? (Year 1 = 2007)
Mathematics
2 answers:
topjm [15]3 years ago
5 0

Answer:

11.38.

Step-by-step explanation:

Given :The price of a movie ticket in a given year can be modeled by the regression equation y = 6.94(1.02^x), where y is the ticket price and x is the year.

To Find: . To the nearest cent, which is the best prediction of the price of a ticket in year 25?

Solution:

y = 6.94(1.02^x)

Where y is the ticket price and x is the year.

Now we are supposed to find which is the best prediction of the price of a ticket in year 25

Substitute x = 25 in the given equation.

y = 6.94(1.02^{25})

y =11.38580

Thus the best prediction of the price of a ticket in year 25 is 11.38.

Whitepunk [10]3 years ago
4 0
I would say that the price would be 176.97.
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A certain drug dosage calls for 17 mg per kg per day and is divided into two doses (1 every 12 hours). If a person weighs 255 po
vekshin1

Answer:

985.15mg

Step-by-step explanation:

Calculation for how many milligrams of the drug should he receive every 12 hours

First step is to calculate the weight in kg

255 lbs = 255/2.2 = 115.9 kg

Second step is multiply mg/kg in order to get total medicine per day

Dose per day=115.9kg × 17 mg

Dose per day= 1,970.3

Third step is to calculate how many milligrams of the drug should he receive by dividing the day dose by 2

Dose milligrams=1,970.3/2

Dose milligrams=985.15mg

Therefore how many milligrams of the drug should he receive every 12 hours will be 985.15mg

3 0
3 years ago
The minimum value of Y in the equation y = x2 - 6x + 8
murzikaleks [220]

Given

y=x^2-6x+8

To obtain the minimum value of y, we first take the derivative of y

The derivative of y is:

y^{\prime}=2x-6

Equating

y^{\prime}\text{ = 0}

gives the minimum value we require.

Doing that, we have:

2x-6=0

So that

\begin{gathered} 2x=6 \\ x=\frac{6}{2} \\ =3 \end{gathered}

Therefore, the minimum value is x = 3

8 0
1 year ago
The average (arithmetic mean) of five different positive integers is 30. What is the greatest possible value of one of these int
geniusboy [140]

Answer:

The Greatest possible value of one of the integer is 140.

Step-by-step explanation:

Given:  The average (arithmetic mean) of five different positive integers is 30.

To find:  What is the greatest possible value of one of these integers?

Explanation: we are given that the arithmetic mean of five  positive integer

                   is 30.

Let the five positive integers are A,B,C,D,E

The arithmetic mean :

                   \frac{A+B+C+D+E}{5} =30.

On multiplying both side by 5.

                       A+B+C+D+E =150.

The least values of A ,B,C and D can be 1 ,2,3,4.

  Then :  1 +2+3+4+E =150

On simplification  10+E =150

On subtraction both side by 10 we get

                      E = 140 .

Therefore, the Greatest possible value of one of the integer is 140.


6 0
3 years ago
6y - 12 = -3x. Write in standard form
bulgar [2K]
3x+6y=12
Hope this helps
5 0
3 years ago
The perimeter of a rectangular garden used 86 feet of barbed wire. The length of the garden is 7 feet more than its width. Find
Taya2010 [7]

Answer:

Step-by-step explanation:

perimeter of a rectangle  = twice the length  plus  twice the width

P = 2L + 2W    equation 1      P = 86 ft

Given the length is seven feet more than the width

L = W + 7         equation 2

Substitute equation 2 into equation 1

P = 2(W+7) + 2W    =  86 ft

     2W +14 + 2W    =  86 ft

     4W    =  86  - 14

        W   =  72 / 4

        W   =  18 feet

6 0
3 years ago
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