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3 years ago

Find the area of a rectangle with the verticies A(-1,-1) B(0,-3) C(4,-1) D(3,1)

Mathematics

1 answer:

ElenaW [278]3 years ago

8 0

Answer:

The Area would be 10.

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PLZ ANSWER ASAP IN NEED OF ANSWERS WILL AWARD BRAINLIEST!!!

Angelina_Jolie [31]

Answer:

△ABC is congruent to △YZX

Step-by-step explanation:

6 0

3 years ago

Thirty students in the fifth grade class listed their hair and eye colors in the table below: Brown hair Blonde hair Total Green

Mars2501 [29]

Answer:

No, the events "brown hair" and "brown eyes" are not independent.

Step-by-step explanation:

The table that represents the hair and eye colors of thirty students of the fifth grade are given in table as:

Brown hair Blonde hair Total

Green eyes 9 6 15

Brown eyes 10 5 15

Total 19 11 30

No, the events "brown hair" and "brown eyes" are not independent.

Since, two events A and B are said to be independent if:

P(A∩B)=P(A)×P(B)

where P denotes the probability of an event.

Here we have:

A= students having brown hair.

B= students having brown eyes.

A∩B= students having both brown hair and brown eyes.

Now,

P(A)=19/30 (ratio of addition of first column to the total entries)

P(B)=15/30 ( ratio of addition of second row to the total entries)

Also,

P(A∩B)=10/30

Now as:

P(A∩B) ≠ P(A)×P(B)

Hence, the two events are not independent.

8 0

3 years ago

39=1 3/10b what will be the answer show work

Lubov Fominskaja [6]

1 3/10·b=39
(1·10+3)·b/10=39
13b/10=39
13b=39·10
13b=390|:13
<u>b=30</u>

<em>Answer: 30</em>

4 0

3 years ago

Use the following area model to multiply 29x97

alexandr402 [8]

The answer to 29×97 would be 2813

6 0

3 years ago

Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

5 0

3 years ago