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3 years ago

Someone pls help I don’t understand!!

Mathematics

2 answers:

lesantik [10]3 years ago

8 0

<h2><u>The correct exponent value is</u><u> 3.</u></h2>

<em>This is scientific notation. . .</em>

In other words, you would move the decimal point of the term being mutliplied by 10^3 to the right three times.

<h3>34.624 x 10^3 would now become 34,624.</h3>

Solnce55 [7]3 years ago

7 0

Answer:

Add a three more zeros at the end

Step-by-step explanation: 34.624*1000=34,624

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Which equation represents the line that passes through the points (-1,-2) and (3,10)

anyanavicka [17]

Answer:

(10+2)/(3+1)= 12/4= 3

y +2= 3(x+1)

y +2=3x+3

y = 3x+1

8 0

3 years ago

The mayor of a town has proposed a plan for the construction of a new community. A political study took a sample of 800 voters i

Hunter-Best [27]

Answer:

A political strategist wants to test the claim that the percentage of residents who favor construction is more than 30%, so then that represent our claim and needs to be on the alternative hypothesis.

Based on this the correct system of hypothesis are:

Null hypothesis: $p \leq 0.3$

Alternative hypothesis $p >0.3$

Step-by-step explanation:

We have the following info given from the problem:

$n= 800$ the random sample of voters selected from the town

$\hat p = 0.34$ represent the proportion of residents favored construction

$p_o = 0.30$ represent the value desired to test.

Based on this the correct system of hypothesis are:

Null hypothesis: $p \leq 0.3$

Alternative hypothesis $p >0.3$

And in order to test this hypothesis we can use a one sample z test for a population proportion and the statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

And with the data given we have:

$z=\frac{0.34 -0.3}{\sqrt{\frac{0.3(1-0.3)}{800}}}=2.469$

7 0

3 years ago

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2