Answer:
$14.39
Step-by-step explanation:
The formula for continuous compounding of interest is:
A = Pe^(rt), were P is the initial dollar amount, A is the final amount, r is the interest rate as a decimal fraction, and t is the time in years.
Here we have $2109 = $500e^(10r) and need to solve for r.
To do this, take the natural log of both sides, obtaining:
ln 2109 = ln 500+ 10r.
Then 10r = ln 2109 - ln 500, and
ln 2109 - ln 500
r = --------------------------------------------
10
= .1439
The interest rate was 14.39%.
I must assume that you meant t=1 (not t=?1). If t=1, here's what we'd do:
1. Find the x and y values corresponding to t=1. They are:
x=(1)^7+1=2 and y=(1)^8+1=2. (Please note: write t^8 instead of t8, and write t^7 instead of t7.)
2. The slope of the tangent line to the graph is
dy/dt 8t^7+1
dy/dx = ---------- = ---------------- with 1 substituted for t
dx/dt 7t^6
Thus, dy/dx (at t=1) = 9/7
3. Now we have both a point (2,2) on the graph and the slope of the tangent line to the curve at that point: 9/7
4. The tangent line to the curve at (2,2) is found by using the point-slope formula:
y-y1 = m(x-x1)
which comes out to y-2 = 9/7(x-2), or 7y-14 = 9(x-2). You could, if you wished, simplify this result further (e. g., by solving for y in terms of x).
We have 225 boxes. And each crate can handle 9 boxes.
Let x = the number of crates to be loader.
9x = 255
Divide both sides by 9
x = 25
Since they both equal y, set the equations equal to each other: 12x + 39 = 9x, simplify
1) 39 = -3x
2) -13 = x
Step-by-step explanation:
y=mx+c
3x-2y+4=0
-2y=-3x+4(divide all sides by -2)
<h2> =y=3/2x-2</h2>
