a) What is the probability that he is accepted to one of the
two schools
this means P( standford or cal-poly)
P( standford or cal-poly) = P( standford) + P(cal-poly) − P(
standford and cal-poly)
= 0.4 + 0.3 – 0.15
= 0.55
What is the probability that he does not get accepted at
either school?
Prob that he gets neither = 1 − 0.55 = 0.45
<span> </span>
This is a problem in which the
percentage and the actual amount are both given. Only thing to do is convert
the percentage to amount.
3% of $600.85 = (3/100) * 600.85
= 1802.55/100
= 18.0255
= 18.03 dollars
So 3% of the amount $600.85 is $18.03.
I hope this was the answer you
were looking for and I have helped you in this matter. If you have understood
the procedure of doing this problem, then in future you can attempt such
problems by your own with absolute ease.
The answer is C,
6:10
6x3 = 18
When you multiply 3 to 6, you do the same to 10. So....
10x3 = 30
You will get
18:30
So it's C
3p : 8s
1p : (8/3)s
So for every one 'p' there is (8/3) 's'
Ratio of p to s is 1 : 8/3
