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uysha [10]
2 years ago
14

The enthalpy change for converting 1.00 mol of ice at -25.0 °c to water at 70.0 °c is __________ kj. the specific heats of ice

, water, and steam are 2
Chemistry
1 answer:
Margarita [4]2 years ago
8 0
Answer is: 6,16 kJ.
1) changing  temperature of ice from -25°C to 0°C.
Q₁ = m·C·ΔT
Q₁ = 18 g · 2 J/g·°C · 25°C 
Q₁ = 900 J.
m(H₂O) = 1mol · 18 g/mol = 18 g.
C - <span>specific heat of ice.
</span>2) changing temperature of water from 0°C to 70°C.
Q₁ = m·C·ΔT
Q₁ = 18 g · 4,18 J/g·°C · 70°C 
Q₁ = 5266,8 J.
C - specific heat of water.
Q = Q₁ + Q₂ = 900 J + 5266,8 J
Q = 6166,8 J = 6,16 kJ.

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Are the properties of Rubidium more similar to those of cesium or those of strontium?
fenix001 [56]

More similar to Cesium

Explanation:

The properties of Rubidium are more similar to those of cesium compared to strontium.

Elements in the same group on the periodic table have similar chemical properties.

  • Rubidium and Cesium are located in the first group on the periodic table.
  • Other elements in this group are lithium, sodium, potassium and francium
  • Strontium belongs to the second group on the periodic table.
  • The first group have a ns¹ valence shells electronic configuration.
  • They are all referred to as alkali metals

Learn more:

Sodium brainly.com/question/6324347

Periodic table brainly.com/question/1704778

#learnwithBrainly

#learnwithBrainly

5 0
3 years ago
Use the ruler to determine the length of this object. Record your answer to the nearest tenth. The object is ____ long.
VLD [36.1K]
The object is 2.7 cm long
7 0
3 years ago
Please answer truthfully:))​
makvit [3.9K]

Answer:

Fast, Direction, Time

Explanation:

4 0
2 years ago
A corpse discovered in the desert at 5:00 PM was found to have larvae from the blow fly species Phormia regina that had just dev
horrorfan [7]

Answer:

12.19 hours prior to discovery was the corpse placed in the desert.

Explanation:

Heat required for fly eggs to develop into first instar larvae = Exposure\,time\times temperature

From the given,

Exposure time = 16 hrs

Temperature = 27 C

=16\times 27 = 427.2^{o}C

The day time exposed hours is 10 hrs.-(7.00am-5.00pm)

=10\times 37.8 = 378^{o}C

So, the extra heat  = 427.2-378= 49.2

The addition heat divided by average temperature.

Average temperature = 22.4 C

=\frac{49.2}{22.4}= 2.19 hrs

So, the total time exposed is night time hours to day time hours.

= 10+2.19 = 12.19 hrs.

Therefore, 12.19 hours prior to discovery was the corpse placed in the desert.

3 0
2 years ago
Sometimes in lab we collect the gas formed by a chemical reaction over water (see sketch at right). This makes it easy to isolat
ad-work [718]

Answer:

The correct answer is 0.00582 grams.

Explanation:

In order to solve the question, let us consider the vapor pressure of H2O, as hydrogen gas is collected over water, therefore, we have to consider the vapor pressure of water in the given case. Let us assume that the pressure is 760 torr or 1 atm.

It is known that the vapor pressure of water at 40 degree C is 53.365 torr (Based on the data).

Therefore, the pressure of H2 will be,

P = 760-55.365 = 704.635 torr or 704.635/760 = 0.9272 atm

The volume of the hydrogen gas collected in the tube is 80 ml or 0.08 L

Temperature in Kelvin will be 40+273 = 313 K

To calculate the moles of hydrogen (H2) gas, there is a need to use the ideal gas equation, that is, PV= nRT, in this R is the gas constant, whose value is 0.0821 L atm/molK, and n is the moles of the gas.

By inserting the values in the equation we get:

PV = nRT

n = PV/RT = 0.9272 *0.08 / 0.0821 * 313

n = 0.00289 moles

The mass of H2 will be moles * molar mass = 0.00289 * 2.016

= 0.00582 grams.

7 0
3 years ago
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