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katrin [286]
3 years ago
6

You could also graph decay time (in seconds or minutes) vs. number of radioactive nuclei. How would this graph differ from the g

raph of cycle number vs. number of radioactive nuclei? Check all that apply. The graph would flip over. The graph would be logarithmic instead of exponential. The x-axis would change title and values. The y-axis would change title and values.
Chemistry
2 answers:
schepotkina [342]3 years ago
8 0
<span>graph is y vs x. so the x-axis is the same: number of radioactive nuclei. But the y-axis </span><span>would change title and values.</span>
Tatiana [17]3 years ago
6 0
Only one of the listed choices are correct here:
<span><em>The x-axis would change title and values.</em>
</span>
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Write Huckel's rule below and determine how many electrons are required to make an aromatic ring with n = 0, 1, and 2.
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<u>Answer:</u> The number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

<u>Explanation:</u>

Huckel's rule is used to determine the aromaticity in a compound. The number of delocalized \pi- electrons are calculated by using the equation:

\text{Number of delocalized }\pi-\text{ electrons}=4n+2

where,

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  • Calculating the value of electrons for n = 0

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(0)+2=2

  • Calculating the value of electrons for n = 1

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(1)+2=6

  • Calculating the value of electrons for n = 2

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(2)+2=10

Hence, the number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

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The O atom will tend to attract the electrons.

Explanation:

The electronegativity of O (3.5) is much higher than H (2.1), which means it is more likely to attract electrons. The higher the electronegativity, the more attractive.

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